Question

Про­во­ди­лась од­но­ка­наль­ная (моно) зву­ко­за­пись с ча­сто­той дискретизации 24 кГц и 16 -бит­ным раз­ре­ше­ни­ем. В ре­зуль­та­те был полу­чен файл раз­ме­ром 30 Мбайт, сжа­тие дан­ных не про­из­во­ди­лось. Какая из при­ве­ден­ных ниже ве­ли­чин наи­бо­лее близ­ка к вре­ме­ни, в те­че­ние ко­то­ро­го про­во­ди­лась за­пись? 1) 9 2) 15 3)20 4)10

Answer 1

Ответ:

Время звукозаписи (сек) t=I/i*n*k, где I- размер файла (бит), i-глубина кодирования звука (бит), n- частота дискретизации(Гц), k- количество каналов звукозаписи.

t= 30*(1024*1024*8)/(16*24000*1)= 655,36 сек = 10,92 минут

Время звукозаписи около 10 минут

Ответ: 4) 10

Объяснение:

Answer 2

Answer in detail. A single-channel (mono) sound recording was made with a sampling rate of 24 kHz and a 16-bit resolution. As a result, a file of 30 MB was obtained, no data compression was performed. Which of the following values is closest to the time during which the recording was made? 1) 9 2) 15 3) 20 4) 10

To answer this question, we need to use the formula for calculating the size of a sound file:

S = f * t * b * n

where S is the size of the file in bytes, f is the sampling frequency in Hz, t is the recording time in seconds, b is the bit depth in bits, and n is the number of channels.

In this case, we have:

S = 30 * 1024 * 1024 bytes (1 MB = 1024 * 1024 bytes) f = 24 * 1000 Hz (1 kHz = 1000 Hz) b = 16 bits n = 1 (mono)

We need to find t, so we rearrange the formula as follows:

t = S / (f * b * n)

Substituting the given values, we get:

t = (30 * 1024 * 1024) / (24 * 1000 * 16 * 1) t = 10.24 seconds

Therefore, the correct answer is 4) 10, as it is the closest value to the actual recording time. You can find more information and examples on sound encoding at [this link](https://www.prodlenka.org/metodicheskie-razrabotki/281476-reshenie-zadach-po-teme-kodirovanie-zvukovoj-).