Question

Дан массив с числами arr = [1, 2, 3, 4, 5]. С помощью цикла найдите сумму квадратов элементов этого массива. Результат: 55нужно на языке python пж​

Answer 1

arr = [1, 2, 3, 4, 5]

s = 0

for i in arr:

   s += i**2

print(s)

Answer 2

Finding the Sum of Squares of Elements in a Python Array

To find the sum of squares of elements in the given array `arr = [1, 2, 3, 4, 5]` in Python, you can use a loop to iterate through the array and calculate the sum of squares. Here's a Python code snippet to achieve this:

arr = [1, 2, 3, 4, 5]
sum_of_squares = 0

for num in arr:
    sum_of_squares += num ** 2

print(sum_of_squares)

When you run this code, the result will be 55. This is because the sum of the squares of the elements in the array `[1, 2, 3, 4, 5]` is calculated as follows: 1^2 + 2^2 + 3^2 + 4^2 + 5^2 = 55.