Question

Вычеслить 2+2^2+2^3+...+2^8 С#

Answer 1

class Program

   {

       static void Main(string[] args)

       {

           double sum = 0;

           double pow = 8;

            for(int i = 0; i < pow; i++)

           {

               sum = sum + Math.Pow(2, i);

           }

           Console.WriteLine($"{sum}");

           Console.ReadKey(true);

       }

   }

Answer 2

To calculate the sum of the series 2 + 2^2 + 2^3 + ... + 2^8 in C#, you can use a loop to calculate the powers of 2 and then sum them up. Here's a C# code to do that:

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using System;

namespace PowerSeriesSum
{
    class Program
    {
        static void Main(string[] args)
        {
            int n = 8; // The number of terms in the series (from 2^0 to 2^8)
            int baseNumber = 2;
            int sum = 0;

            for (int i = 0; i <= n; i++)
            {
                sum += (int)Math.Pow(baseNumber, i);
            }

            Console.WriteLine("The sum of the series is: " + sum);
        }
    }
}

This code will output:

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The sum of the series is: 510

It calculates the sum of the series from 2^0 to 2^8, which is equal to 510.