Question

Var s,k: integer; begin s := 0; for k := 1 to 11 do s := s + 12; writeln(s); end.

Answer 1

Ответ 132. Т.к цикл проработает 11 раз

12*11 = 132

Answer 2

Let's analyze the code you provided:

pascalCopy code
Var s, k: integer;
begin
  s := 0;
  for k := 1 to 11 do
    s := s + 12;
  writeln(s);
end.

This Pascal code declares two variables s and k, both of type integer. It then initializes the variable s to 0.

Next, it enters a loop that iterates from 1 to 11 (inclusive) using the loop variable k. Within the loop, it adds 12 to the variable s in each iteration.

After the loop finishes executing, the code prints the value of s using writeln(s).

Let's calculate the final value of s after the loop:

In each iteration of the loop, s is incremented by 12. Since the loop runs 11 times (from 1 to 11), the value of s will be 12 times the number of iterations, which is 12 * 11 = 132.

Therefore, the output of this code will be:

Copy code
132