Question

Y=1^1+2^2+3^3+...n напишите программу

Answer 1

Type
Tmas = array [1..100] of longint;

var
m: Tmas;
i, j, proiz, N, sohr: longint;
begin
proiz := 0;
readln(N);
for i := 1 to N do
begin
readln(m[i]);
sohr := m[i];
for j := 1 to sohr - 1 do
begin
m[i] := m[i] * sohr;
end;
proiz := proiz + m[i];
end;
writeln(proiz);
end.

Answer 2

Sure! It seems like you want to calculate the sum of powers from 1 to n, where each term is raised to its own power. Here's a Python program that does that:

pythonCopy code
def calculate_sum_of_powers(n):
    total_sum = 0
    for i in range(1, n + 1):
        total_sum += i ** i
    return total_sum

# Input the value of n from the user
try:
    n = int(input("Enter the value of n: "))
    if n < 1:
        print("Please enter a positive integer greater than or equal to 1.")
    else:
        result = calculate_sum_of_powers(n)
        print(f"The sum of powers from 1 to {n} is: {result}")
except ValueError:
    print("Invalid input. Please enter a valid integer.")

Save the above code in a Python file (e.g., sum_of_powers.py) and run it. The program will prompt you to enter the value of n, and then it will calculate and display the sum of powers from 1 to n.