Question

1) 131 div 100 = 2) 77 mod 2 div 14 = 3) 121 mod 100 div 2 = 4) 222 div 2 mod 2 = 5) 65 mod 12 = Срочно пожалуйста...​

Answer 1

Ответ:

1 =1

2 =0

3 =10

4 =1

5 =5

Объяснение:

Это обычне выражения, которые можно просто решить, но и также можно составить программу:

program Hello;

var a,b,c,d,e : integer;

begin

a := 131 div 100;

 writeln ('1 =', a);

 b := 77 mod 2 div 14;

 writeln ('2 =', b);

 c := 121 mod 100 div 2;

 writeln ('3 =', c);

 d := 222 div 2 mod 2;

 writeln ('4 =', d);

 e := 65 mod 12;

 writeln ('5 =', e);

end.

Answer 2

1. 131 divided by 100 is 1.31.
2. Taking 77 modulo 2 (remainder of division) results in 1. Dividing 1 by 14 gives approximately 0.07.
3. Taking 121 modulo 100 gives 21. Dividing 21 by 2 results in 10.5.
4. Dividing 222 by 2 gives 111. Taking 111 modulo 2 results in 1.
5. Taking 65 modulo 12 (remainder of division) gives 5.

So, the answers are:

1. 1.31
2. 0.07
3. 10.5
4. 1
5. 5