Question

A:=-(2+3*(10-7)) b:=(22/a)*(33/a) b:=b/2 информатика​ срочно кто-нибудь решите

Answer 1

Порядок выполнения решений:

1) Раскрываются скобки.

2) Умножения и деления.

3) Плюсы и минусы.

1) a:=-(2+3*(10-7)) = -(2+3*3) = - 11

2) b:=(22/a)*(33/a) = (22/(- 11))*(33/(- 11)) = (-2)*(-3) = 6

3)  b:=b/2 = 6/2 = 3

Answer 2

To solve this problem, we need to substitute the value of A into the expression for B and then evaluate B.

First, let's evaluate A:

A = -(2 + 3*(10-7)) A = -(2 + 3*3) A = -(2 + 9) A = -11

Now we can substitute A into the expression for B:

B = (22/A)(33/A) B = (22/-11)(33/-11) B = (-2)*(3) B = -6

Finally, we divide B by 2:

B = B/2 B = -6/2 B = -3

Therefore, the final value of B is -3.