Question

Навеску натрия массой 6,9 г опустили в стакан с водой. Найдите объём выделившегося водорода.

Answer 1

Calculation of the Volume of Hydrogen Gas Released

To find the volume of hydrogen gas released when a mass of sodium (6.9 g) is submerged in water, we need to use the concept of stoichiometry. The balanced chemical equation for the reaction between sodium and water is:

2Na + 2H2O -> 2NaOH + H2

From the balanced equation, we can see that 2 moles of sodium react with 2 moles of water to produce 1 mole of hydrogen gas.

To calculate the volume of hydrogen gas, we need to convert the mass of sodium to moles using its molar mass. The molar mass of sodium (Na) is approximately 22.99 g/mol.

Let's calculate the number of moles of sodium:

Number of moles of sodium = mass of sodium / molar mass of sodium Number of moles of sodium = 6.9 g / 22.99 g/mol

Now, we can use the mole ratio from the balanced equation to find the number of moles of hydrogen gas produced:

Number of moles of hydrogen gas = (Number of moles of sodium) / 2

Finally, we can use the ideal gas law to calculate the volume of hydrogen gas:

Volume of hydrogen gas = (Number of moles of hydrogen gas) * (22.4 L/mol)

Let's calculate the volume of hydrogen gas:

Number of moles of sodium = 6.9 g / 22.99 g/mol = 0.300 mol Number of moles of hydrogen gas = 0.300 mol / 2 = 0.150 mol Volume of hydrogen gas = 0.150 mol * 22.4 L/mol = 3.36 L

Therefore, the volume of hydrogen gas released when a mass of sodium (6.9 g) is submerged in water is approximately 3.36 liters.