Question

К каждому полное и сокращеное ионое уравнение Cu(OH)2+HNO3= NaCl+AgNO3= Na2SO3+H2SO4= MgSO4+KOH=

Answer 1

Cu(OH)2 + HNO3

The reaction between Cu(OH)2 (copper hydroxide) and HNO3 (nitric acid) can be represented by the following balanced chemical equation:

Cu(OH)2 + 2HNO3 → Cu(NO3)2 + 2H2O [[1]](http://eprints.kname.edu.ua/37168/1/%282013%20%D0%BF%D0%B5%D1%87.%20%2022%D0%9D%20POSOBIE%2012%20%D0%BA%D0%B5%D0%B3%D0%B5%D0%BB%D1%8C%29.pdf)

NaCl + AgNO3

The reaction between NaCl (sodium chloride) and AgNO3 (silver nitrate) can be represented by the following balanced chemical equation:

NaCl + AgNO3 → AgCl + NaNO3

Na2SO3 + H2SO4

The reaction between Na2SO3 (sodium sulfite) and H2SO4 (sulfuric acid) can be represented by the following balanced chemical equation:

Na2SO3 + H2SO4 → Na2SO4 + H2O + SO2

MgSO4 + KOH

The reaction between MgSO4 (magnesium sulfate) and KOH (potassium hydroxide) can be represented by the following balanced chemical equation:

MgSO4 + 2KOH → Mg(OH)2 + K2SO4 Please note that these equations represent the balanced chemical reactions between the given compounds.