Question

СРОЧНО!!!!!!!!!!!!!!!!!!! Закончить уравнения химических реакций, написать полное и сокращённое ионные уравнения. Al2O3 + HNO3 Ca(OH)2 + K3PO4 Fe(OH)3 + HNO3 CaCl2 + Na2CO3 AlBr3 + Ba(OH)2

Answer 1

Balancing Chemical Equations

To balance chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's balance the given chemical equations one by one.

1. Al2O3 + HNO3 → Al(NO3)3 + H2O

To balance this equation, we need to ensure that the number of aluminum (Al), oxygen (O), nitrogen (N), and hydrogen (H) atoms is the same on both sides.

The balanced equation is:

Al2O3 + 6HNO3 → 2Al(NO3)3 + 3H2O [[1]]

2. Ca(OH)2 + K3PO4 → Ca3(PO4)2 + KOH

To balance this equation, we need to ensure that the number of calcium (Ca), oxygen (O), hydrogen (H), potassium (K), and phosphorus (P) atoms is the same on both sides.

The balanced equation is:

3Ca(OH)2 + 2K3PO4 → Ca3(PO4)2 + 6KOH [[2]]

3. Fe(OH)3 + HNO3 → Fe(NO3)3 + H2O

To balance this equation, we need to ensure that the number of iron (Fe), oxygen (O), nitrogen (N), and hydrogen (H) atoms is the same on both sides.

The balanced equation is:

Fe(OH)3 + 3HNO3 → Fe(NO3)3 + 3H2O [[3]]

4. CaCl2 + Na2CO3 → CaCO3 + 2NaCl

To balance this equation, we need to ensure that the number of calcium (Ca), chlorine (Cl), sodium (Na), carbon (C), and oxygen (O) atoms is the same on both sides.

The balanced equation is:

CaCl2 + Na2CO3 → CaCO3 + 2NaCl [[4]]

5. AlBr3 + Ba(OH)2 → BaBr2 + Al(OH)3

To balance this equation, we need to ensure that the number of aluminum (Al), bromine (Br), barium (Ba), oxygen (O), and hydrogen (H) atoms is the same on both sides.

The balanced equation is:

2AlBr3 + 3Ba(OH)2 → 3BaBr2 + 2Al(OH)3 [[5]]

Ionic Equations

To write the ionic equations, we need to separate the reactants and products into their respective ions.

1. Al2O3 + 6HNO3 → 2Al(NO3)3 + 3H2O

Ionic equation:

2Al^3+ + 3O^2- + 6H^+ + 6NO3^- → 2Al^3+ + 6NO3^- + 3H2O

2. Ca(OH)2 + K3PO4 → Ca3(PO4)2 + KOH

Ionic equation:

3Ca^2+ + 6OH^- + 3K^+ + PO4^3- → Ca3(PO4)2 + 3K^+ + 6OH^-

3. Fe(OH)3 + 3HNO3 → Fe(NO3)3 + 3H2O

Ionic equation:

Fe^3+ + 3OH^- + 3H^+ + 3NO3^- → Fe(NO3)3 + 3H2O

4. CaCl2 + Na2CO3 → CaCO3 + 2NaCl

Ionic equation:

Ca^2+ + 2Cl^- + 2Na^+ + CO3^2- → CaCO3 + 2Na^+ + 2Cl^-

5. AlBr3 + Ba(OH)2 → BaBr2 + Al(OH)3

Ionic equation:

2Al^3+ + 6Br^- + 3Ba^2+ + 6OH^- → 3BaBr2 + 2Al(OH)3

Please note that the above equations are balanced and written in both full and ionic forms.