Question

2,14г металла вытесняют из кислоты  2 дм3 водорода при нормальных условиях.Определите молярную эквивалентную массу гидроксида металла.

Answer 1

I will answer your question in detail. 2.14 g of metal displace 2 dm3 of hydrogen from acid under normal conditions. Determine the molar equivalent mass of the metal hydroxide.

According to the web search results, the metal is magnesium (Mg) and the reaction is as follows:

Mg + 2HCl = MgCl2 + H2

To determine the molar equivalent mass of the metal hydroxide, we need to use the following formula:

Molar equivalent mass = Molar mass / Valence

The molar mass of Mg is 24 g/mol and the valence of Mg is 2, so the molar equivalent mass of Mg is 24/2 = 12 g/mol.

The molar mass of Mg(OH)2 is 58 g/mol and the valence of Mg(OH)2 is 2, so the molar equivalent mass of Mg(OH)2 is 58/2 = 29 g/mol.

Therefore, the molar equivalent mass of the metal hydroxide is 29 g/mol. I hope this helps.