
NH4Cl+NaNO2=N2+NaCl+Н2О-электронный баланс методом полуреакций


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Electrochemical Balance Method for NH4Cl + NaNO2 = N2 + NaCl + H2O
To balance the chemical equation NH4Cl + NaNO2 = N2 + NaCl + H2O using the electrochemical balance method, we need to break down the reaction into two half-reactions: the oxidation half-reaction and the reduction half-reaction.
The oxidation half-reaction involves the loss of electrons, while the reduction half-reaction involves the gain of electrons. By balancing the number of electrons in each half-reaction, we can then combine them to obtain the balanced overall equation.
Let's start by identifying the oxidation and reduction half-reactions:
Oxidation Half-Reaction: NH4Cl -> N2
Reduction Half-Reaction: NaNO2 -> NaCl + H2O
Now, let's balance each half-reaction individually:
Oxidation Half-Reaction: The oxidation half-reaction involves the conversion of NH4Cl to N2. To balance the number of nitrogen atoms, we need to multiply NH4Cl by 2:
2NH4Cl -> N2
Reduction Half-Reaction: The reduction half-reaction involves the conversion of NaNO2 to NaCl and H2O. To balance the number of oxygen atoms, we need to multiply NaNO2 by 2:
2NaNO2 -> 2NaCl + H2O
Now that we have balanced the individual half-reactions, we can combine them to obtain the balanced overall equation:
2NH4Cl + 2NaNO2 -> N2 + 2NaCl + H2O
Please note that this is a balanced equation using the electrochemical balance method. If you have any further questions, feel free to ask!


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