Question

Рассчитайте химическое количество ионов натрия, которые образуются при растворении в воде сульфата натрия массой 5 г. В растворе содержаться ионы калия химическим количеством 0.24 моль. Определите массу сульфата калия, который содержится в этом растворе.

Answer 1

1.m(Na2so4)=5 г  
Na2SO4+2H2O=2NaOH+H2SO4
n(Na+)=n(NA2SO4)*2=(m(Na2so4)/M(Na2so4))*2=5*2/142=0,08 моль
2. k2so4+2h2o=2koh+h2so4
m(k2so4)=n(k2so4)*M(k2so4)     n(k2so4)=n(K+)/2=0.12 моль
m(k2so4)=0.12*175=21 г

Answer 2

Calculation of Chemical Amount of Sodium Ions

To calculate the chemical amount of sodium ions formed when dissolving sodium sulfate in water, we need to know the molar mass of sodium sulfate and the mass of sodium sulfate used.

The molar mass of sodium sulfate (Na2SO4) can be calculated by adding up the atomic masses of its constituent elements: - Sodium (Na) has an atomic mass of 22.99 g/mol. - Sulfur (S) has an atomic mass of 32.07 g/mol. - Oxygen (O) has an atomic mass of 16.00 g/mol.

The molar mass of sodium sulfate is therefore: (2 * 22.99 g/mol) + 32.07 g/mol + (4 * 16.00 g/mol) = 142.04 g/mol.

Given that the mass of sodium sulfate used is 5 g, we can calculate the chemical amount of sodium sulfate using the following formula:

Chemical amount (in moles) = Mass (in grams) / Molar mass (in g/mol)

Chemical amount of sodium sulfate = 5 g / 142.04 g/mol = 0.0352 mol

Since sodium sulfate dissociates into two sodium ions (Na+) per formula unit, the chemical amount of sodium ions formed will be twice the chemical amount of sodium sulfate:

Chemical amount of sodium ions = 2 * Chemical amount of sodium sulfate Chemical amount of sodium ions = 2 * 0.0352 mol = 0.0704 mol

Therefore, the chemical amount of sodium ions formed when dissolving 5 g of sodium sulfate in water is 0.0704 mol.

Calculation of Mass of Potassium Sulfate

To determine the mass of potassium sulfate (K2SO4) present in the solution, we need to know the chemical amount of potassium ions (K+) and the molar mass of potassium sulfate.

Given that the chemical amount of potassium ions is 0.24 mol, we can calculate the chemical amount of potassium sulfate using the following formula:

Chemical amount of potassium sulfate = Chemical amount of potassium ions / 2

Chemical amount of potassium sulfate = 0.24 mol / 2 = 0.12 mol

The molar mass of potassium sulfate can be calculated by adding up the atomic masses of its constituent elements: - Potassium (K) has an atomic mass of 39.10 g/mol. - Sulfur (S) has an atomic mass of 32.07 g/mol. - Oxygen (O) has an atomic mass of 16.00 g/mol.

The molar mass of potassium sulfate is therefore: (2 * 39.10 g/mol) + 32.07 g/mol + (4 * 16.00 g/mol) = 174.26 g/mol.

To calculate the mass of potassium sulfate, we can use the following formula:

Mass (in grams) = Chemical amount (in moles) * Molar mass (in g/mol)

Mass of potassium sulfate = 0.12 mol * 174.26 g/mol = 20.91 g

Therefore, the mass of potassium sulfate present in the solution is 20.91 g.

Summary: - The chemical amount of sodium ions formed when dissolving 5 g of sodium sulfate in water is 0.0704 mol. - The mass of potassium sulfate present in the solution is 20.91 g.

Please note that the calculations provided are based on the given information and assumptions.