Question

Вычислить какая масса соли получится при нейтрализации 4-х грамм гидроксида натрия фосфоной кислотой.

Answer 1

3NaOH+H3PO4=Na3PO4 + 3H2O
n(NaOH)=m/M=4/23=0.17 моль
n(NaOH)/3=n(Na3PO4)/1
n(Na3PO4)=0.57 моль

m(Na3PO4)=n*M=0.57*164=93.5 г

Answer 2

Calculation of Salt Mass in the Neutralization Reaction

To calculate the mass of salt produced during the neutralization of 4 grams of sodium hydroxide with phosphonic acid, we need to determine the balanced chemical equation for the reaction. Unfortunately, the search results provided do not include the specific balanced equation for the neutralization of sodium hydroxide with phosphonic acid. Therefore, I am unable to provide a precise answer based on the available information.

However, I can provide you with some general information about neutralization reactions and how to calculate the mass of salt produced in such reactions.

In a neutralization reaction, an acid reacts with a base to form a salt and water. The balanced chemical equation for a neutralization reaction typically follows the general form:

Acid + Base → Salt + Water

To calculate the mass of salt produced, you need to know the balanced chemical equation and the molar masses of the reactants and products involved. From the available search results, we can see that the molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol However, we do not have the molar mass of phosphonic acid or the balanced chemical equation for the reaction.

Without the specific balanced equation and the molar mass of phosphonic acid, it is not possible to calculate the mass of salt produced in the neutralization reaction. To obtain an accurate answer, you would need to provide the balanced chemical equation or additional information about the reaction.

If you have any further questions or need assistance with another topic, feel free to ask!