Question

Определите массовую долю СuSO4 в растворе, полученном при смешивании 120 гр. 5% -ного и 80 гр. 25% -ного раствора CuSO4

Answer 1

Найдем количество вещества медного купороса 50/250= 0,2 моль. Масса сульфата меди при этом будет 0,2*160= 32г, в поды следовательно 50-32 = 18 г. Тогда массовая доля будет (32/(18+450))*100% = 6,84%

Answer 2

Calculation of the Mass Fraction of CuSO4 in the Solution

To determine the mass fraction of CuSO4 in the solution obtained by mixing 120 grams of a 5% CuSO4 solution and 80 grams of a 25% CuSO4 solution, we need to calculate the total mass of CuSO4 in the mixture and then divide it by the total mass of the solution.

Let's calculate the mass of CuSO4 in each solution:

- Mass of CuSO4 in the 5% solution: - Mass = 5% * 120 grams = 0.05 * 120 grams = 6 grams.

- Mass of CuSO4 in the 25% solution: - Mass = 25% * 80 grams = 0.25 * 80 grams = 20 grams.

Now, let's calculate the total mass of CuSO4 in the mixture:

- Total mass of CuSO4 = Mass of CuSO4 in the 5% solution + Mass of CuSO4 in the 25% solution - Total mass of CuSO4 = 6 grams + 20 grams = 26 grams.

Next, we need to calculate the total mass of the solution:

- Total mass of the solution = Mass of the 5% solution + Mass of the 25% solution - Total mass of the solution = 120 grams + 80 grams = 200 grams.

Finally, we can calculate the mass fraction of CuSO4 in the solution:

- Mass fraction of CuSO4 = (Total mass of CuSO4 / Total mass of the solution) * 100% - Mass fraction of CuSO4 = (26 grams / 200 grams) * 100% = 13%.

Therefore, the mass fraction of CuSO4 in the solution obtained by mixing 120 grams of a 5% CuSO4 solution and 80 grams of a 25% CuSO4 solution is 13%.

Please note that the calculations provided are based on the given information and assumptions.