Question

В состав молекулы соединения азота с кислородом входят три атома кислорода.относительная молекулярная масса этого вещества равна 76. Устоновите химическую формулу этого вещества и определите массовые доли атомов каждого элемента в нем.

Answer 1

1) найдем массу, приходящуюся на атомы азота: 76- (16*3)=28.
 значит, в молекуле 2 атома азота: 2)  28: 14 = 2
3) найдем м.д. атомов кислорода : w(O)= 4800: 76=65%
4) м.д. атомов азота w (N)=100-65=35%

Answer 2

Analysis

The question provides the following information: - The compound contains nitrogen and oxygen atoms. - It contains 3 oxygen atoms. - Its relative molecular mass is 76.

Determining the Chemical Formula

Based on the information given: - Nitrogen (N) has a mass of 14 amu - Oxygen (O) has a mass of 16 amu - The compound contains 3 oxygen atoms - So the total mass of the oxygen atoms is 3 * 16 = 48 amu - The remaining mass must be due to nitrogen - So the nitrogen mass is 76 - 48 = 28 amu - Nitrogen has a mass of 14 amu - So there must be 28/14 = 2 nitrogen atoms - Therefore, the chemical formula is N2O3

Determining Mass Percentages

To determine the mass percentages of each element: - Nitrogen (N) mass = 2 * 14 = 28 amu - Oxygen (O) mass = 3 * 16 = 48 amu - Total molecular mass = 28 + 48 = 76 amu - Mass percentage of N = (Mass of N/Total Mass) * 100 = (28/76) * 100 = 36.8% - Mass percentage of O = (Mass of O/Total Mass) * 100 = (48/76) * 100 = 63.2%