Question

надо записать в молекулярном и сокращенном ионном молекулярном виде уравнения: дигидрофосфат железа III + H2SO4 помогите

Answer 1

2Fe(H2PO4)3+3H2SO4=Fe2(SO4)3+6H3PO4

2Fe(H2PO4)3+3SO4(2-)=2Fe(3+)+3SO4(2-)+12H(+)+6PO4(3-)

Answer 2

Reaction in Molecular and Ionic Form

The reaction of ferric hydrophosphate and sulfuric acid can be written in molecular and ionic forms as follows:

Molecular form: FePO4(H2PO4) + H2SO4 → FeSO4 + H3PO4 + H2O

Ionic form: FePO4(H2PO4) + H+ + SO42- → Fe3+ + HPO42- + H3PO4 + H2O

Where: - FePO4(H2PO4) is ferric hydrophosphate - H2SO4 dissociates into H+ and SO42- ions in water - The reaction results in ferric sulfate (FeSO4), phosphoric acid (H3PO4), and water (H2O)

The ferric ion (Fe3+) displaces the hydrogen ion from phosphoric acid (H3PO4) in the reaction. Sulfuric acid acts as a source of hydronium ions (H+) which help drive the reaction forward by removing H+ from ferric hydrophosphate.