Question

C+O2=Co2 в свете ОВРCaCl2+Na2Co3=CaCo3+2NaCl в свете ТЭД

Answer 1

C°+O°₂=C⁺⁴o⁻²₂
C°-4е=C⁺⁴ -восст
O°₂+4е=o⁻²₂ - окисл

CaCl₂+Na₂Co₃=CaCo₃(осадок)+2NaCl в свете ТЭД
Сa⁺²+2CI⁻+2Na⁺+CO₃⁻³=CaCo₃(осадок)+2Na⁺+2CI⁻(одинаковые ионы в левой и правой частях уравнения, уходят из раствора, переписываем то что осталось)
Сa⁺²+CO₃⁻³=CaCo₃(осадок)

Answer 2

Reaction 1: C + O2 = CO2

The reaction between carbon (C) and oxygen (O2) produces carbon dioxide (CO2) in the presence of light. This reaction is a combustion reaction, where carbon reacts with oxygen to form carbon dioxide. The balanced chemical equation for this reaction is:

C + O2 → CO2

Reaction 2: CaCl2 + Na2CO3 = CaCO3 + 2NaCl

The reaction between calcium chloride (CaCl2) and sodium carbonate (Na2CO3) produces calcium carbonate (CaCO3) and sodium chloride (NaCl) in the presence of light. This reaction is a double displacement reaction, where the cations and anions of the reactants switch places to form new compounds. The balanced chemical equation for this reaction is:

CaCl2 + Na2CO3 → CaCO3 + 2NaCl Please note that the phrase "в свете" translates to "in the presence of light" in English.

Additional Information

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