Question

Закончите уравнения возможных реакций. BaO+P2O5=; H2O+BaO=; H2SO4+Li2o=; NaOH+CaO=; Li2O+SO2=

Answer 1

3BaO+P2O5=Ba3(PO4)2
H2O+BaO=Ba(OH)2
H2SO4+Li2O=Li2SO4+H2O
NaOH+CaO≠
Li2O+SO2=Li2SO3

Answer 2

BaO + P2O5 =

The reaction between Barium Oxide (BaO) and Phosphorus Pentoxide (P2O5) can be represented as follows:

BaO + P2O5 → Ba(PO3)2

H2O + BaO =

The reaction between Water (H2O) and Barium Oxide (BaO) can be represented as follows:

H2O + BaO → Ba(OH)2

H2SO4 + Li2O =

The reaction between Sulfuric Acid (H2SO4) and Lithium Oxide (Li2O) can be represented as follows:

H2SO4 + Li2O → Li2SO4 + H2O

NaOH + CaO =

The reaction between Sodium Hydroxide (NaOH) and Calcium Oxide (CaO) can be represented as follows:

2NaOH + CaO → Na2O + Ca(OH)2

Li2O + SO2 =

The reaction between Lithium Oxide (Li2O) and Sulfur Dioxide (SO2) can be represented as follows:

Li2O + SO2 → Li2SO3 Please note that these equations represent the possible reactions based on the given reactants. The actual occurrence of these reactions may depend on various factors such as reaction conditions, stoichiometry, and other reactants present.