Question

расствьте коэффициенты (если можно покажите как расставляли коэффициенты) в схемах следующих реакций и определите типы реакций:1) CaO+HCL=CaCL2+H2O2) Na+I2=NaI3) Zn+ CuSO4=Cu+ZnSO44) Ba + O2=BaO5)Mg+N2=Mg3N26)AgNo3=Ag+NO2+O27)AgF+Na2S=Ag2S+NaF8)HgO=Hg+O29)MnO+O2=Mn3O410)Cu+O2=CuO

Answer 1

CaO+2HCl=CaCl2+H2O

2Na+I2=2NaI

 

 Zn+CuSO4=Cu+ZnSO4 

2Ba+O2=2BaO

 

 3Mg+N2=Mg3N2

2AgNO3=2Ag+2NO2+O2

 

 2AgF+Na2S=Ag2S+2NaF

2HgO=2Hg+O2

 

 6MnO+O2=2Mn3O4

2Cu+O2=2CuO

 

 Как раставлять коэффициенты..надо чтобы в левой и правой части они совпадали 
например H2+O2=H2O влевой части О(кислорода) 2, а вправой его 1,значит перед H2O ставим коэффициент 2.. 

Answer 2

Reaction 1: CaO + HCl = CaCl2 + H2O

To determine the coefficients and types of reactions, we can balance the equation by following these steps:

1. Start by counting the number of atoms on each side of the equation. - Left side: 1 Ca, 1 O, 1 H, 1 Cl - Right side: 1 Ca, 2 Cl, 2 H, 1 O

2. Balance the atoms one by one, starting with the most complex molecule. - Balance the calcium (Ca) atoms: Add a coefficient of 1 in front of CaCl2. - Now the equation becomes: CaO + HCl = 1 CaCl2 + H2O

3. Balance the chlorine (Cl) atoms: Add a coefficient of 2 in front of HCl. - Now the equation becomes: CaO + 2 HCl = 1 CaCl2 + H2O

4. Balance the hydrogen (H) atoms: Add a coefficient of 2 in front of H2O. - Now the equation becomes: CaO + 2 HCl = 1 CaCl2 + 2 H2O

5. Balance the oxygen (O) atoms: Add a coefficient of 1 in front of CaO. - Now the equation becomes: 1 CaO + 2 HCl = 1 CaCl2 + 2 H2O

The balanced equation is: CaO + 2 HCl = CaCl2 + 2 H2O.

The type of reaction is a double displacement reaction because the calcium oxide (CaO) and hydrochloric acid (HCl) react to form calcium chloride (CaCl2) and water (H2O).

Reaction 2: Na + I2 = NaI

To balance the equation and determine the type of reaction:

1. Count the number of atoms on each side of the equation. - Left side: 1 Na, 1 I - Right side: 1 Na, 1 I

2. The equation is already balanced.

The balanced equation is: Na + I2 = NaI.

The type of reaction is a single displacement reaction because sodium (Na) displaces iodine (I) from iodine molecules (I2) to form sodium iodide (NaI).

Reaction 3: Zn + CuSO4 = Cu + ZnSO4

To balance the equation and determine the type of reaction:

1. Count the number of atoms on each side of the equation. - Left side: 1 Zn, 1 Cu, 1 S, 4 O - Right side: 1 Cu, 1 Zn, 1 S, 4 O

2. The equation is already balanced.

The balanced equation is: Zn + CuSO4 = Cu + ZnSO4.

The type of reaction is a single displacement reaction because zinc (Zn) displaces copper (Cu) from copper sulfate (CuSO4) to form copper (Cu) and zinc sulfate (ZnSO4).

Reaction 4: BaO2 + O2 = BaO

To balance the equation and determine the type of reaction:

1. Count the number of atoms on each side of the equation. - Left side: 1 Ba, 2 O - Right side: 1 Ba, 1 O

2. Balance the oxygen (O) atoms: Add a coefficient of 2 in front of BaO. - Now the equation becomes: BaO2 + O2 = 2 BaO

3. The equation is already balanced.

The balanced equation is: BaO2 + O2 = 2 BaO.

The type of reaction is a combination reaction because barium peroxide (BaO2) reacts with oxygen (O2) to form barium oxide (BaO).

Reaction 5: Mg + N2 = Mg3N2

To balance the equation and determine the type of reaction:

1. Count the number of atoms on each side of the equation. - Left side: 1 Mg, 1 N - Right side: 3 Mg, 2 N

2. Balance the magnesium (Mg) atoms: Add a coefficient of 3 in front of Mg. - Now the equation becomes: 3 Mg + N2 = Mg3N2

3. The equation is already balanced.

The balanced equation is: 3 Mg + N2 = Mg3N2.

The type of reaction is a combination reaction because magnesium (Mg) reacts with nitrogen (N2) to form magnesium nitride (Mg3N2).

Reaction 6: AgNO3 = Ag + NO2 + O2

To balance the equation and determine the type of reaction:

1. Count the number of atoms on each side of the equation. - Left side: 1 Ag, 1 N, 3 O - Right side: 1 Ag, 1 N, 3 O

2. The equation is already balanced.

The balanced equation is: AgNO3 = Ag + NO2 + O2.

The type of reaction is a decomposition reaction because silver nitrate (AgNO3) decomposes into silver (Ag), nitrogen dioxide (NO2), and oxygen (O2).

Reaction 7: AgF + Na2S = Ag2S + NaF

To balance the equation and determine the type of reaction:

1. Count the number of atoms on each side of the equation. - Left side: 1 Ag, 1 F, 2 Na, 1 S - Right side: 2 Ag, 1 S, 2 Na, 1 F

2. Balance the silver (Ag) atoms: Add a coefficient of 2 in front of AgF. - Now the equation becomes: 2 AgF + Na2S = Ag2S + NaF

3. The equation is already balanced.

The balanced equation is: 2 AgF + Na2S = Ag2S + NaF.

The type of reaction is a double displacement reaction because silver fluoride (AgF) and sodium sulfide (Na2S) react to form silver sulfide (Ag2S) and sodium fluoride (NaF).

Reaction 8: HgO = Hg + O2

To balance the equation and determine the type of reaction:

1. Count the number of atoms on each side of the equation. - Left side: 1 Hg, 1 O - Right side: 1 Hg, 2 O

2. Balance the oxygen (O) atoms: Add a coefficient of 2 in front of HgO. - Now the equation becomes: 2 HgO = 2 Hg + O2

3. The equation is already balanced.

The balanced equation is: 2 HgO = 2 Hg + O2.

The type of reaction is a decomposition reaction because mercury(II) oxide (HgO) decomposes into mercury (Hg) and oxygen (O2).

Reaction 9: MnO + O2 = Mn3O4

To balance the equation and determine the type of reaction:

1. Count the number of atoms on each side of the equation. - Left side: 1 Mn, 1 O - Right side: 3 Mn, 4 O

2. Balance the manganese (Mn) atoms: Add a coefficient of 3 in front of MnO. - Now the equation becomes: 3 MnO + O2 = Mn3O4

3. The equation is already balanced.

The balanced equation is: 3 MnO + O2 = Mn3O4.

The type of reaction is a combination reaction because manganese(II) oxide (MnO) reacts with oxygen (O2) to form manganese(III) oxide (Mn3O4).

Reaction 10: Cu + O2 = CuO

To balance the equation and determine the type of reaction:

1. Count the number of atoms on each side of the equation. - Left side: 1 Cu, 2 O - Right side: 1 Cu, 1 O

2. Balance the oxygen (O) atoms: Add a coefficient of 2 in front of CuO. - Now the equation becomes: Cu + O2 = 2 CuO

3. The equation is already balanced.

The balanced equation is: Cu + O2 = 2 CuO.

The type of reaction is a combination reaction because copper (Cu) reacts with oxygen (O2) to form copper(II) oxide (CuO).

Please note that the coefficients and types of reactions were determined by balancing the equations and considering the information provided.