Вопрос задан 11.05.2019 в 02:38. Предмет Химия. Спрашивает Красавин Иван.

Даю 80 баллов за правильный и быстрый ответ!!! *************************** Получи раствор соли 2гр.

Вычислить массу водорода который можно получить при взаимодействии магния с раствором кислоты с массой 490грамм и массовой долей H2SO4-10%
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Отвечает Поляков Васян.
Mg + H2SO4 =》MgSO4 + H2
m(H2SO4)= 490 * 0.1 = 49
n (H2SO4)= 49/98 = 0.5моль
n (H2) = 0.5 моль
m (H2)= 2*0.5= 1 г
ответ:1 г
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Отвечает Рябчикова Дарья.
Дано:
m(раствора)=490 г(10% H2SO4)
Найти:
m(H2)=? 

Решение:
Mg+H2SO4=MgSO4+H2
M(H2SO4)=98 г/моль, M(H2)=2 г/моль
m(H2SO4)=490x0.1=49(г)
49/98=x/2
x=1
m(H2)=1(г)
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

To calculate the mass of hydrogen that can be obtained from the reaction between magnesium and a solution of sulfuric acid, we need to consider the balanced chemical equation for the reaction and use stoichiometry.

The balanced chemical equation for the reaction between magnesium (Mg) and sulfuric acid (H2SO4) is as follows:

Mg + H2SO4 → MgSO4 + H2

From the equation, we can see that 1 mole of magnesium reacts with 1 mole of sulfuric acid to produce 1 mole of hydrogen gas.

To calculate the mass of hydrogen gas produced, we need to determine the number of moles of sulfuric acid and then use stoichiometry to find the number of moles of hydrogen gas. Finally, we can convert the moles of hydrogen gas to grams using the molar mass of hydrogen.

Let's calculate step by step:

Step 1: Calculate the number of moles of sulfuric acid (H2SO4)

Given: - Mass of sulfuric acid = 490 grams - Mass fraction of sulfuric acid in the solution = 10%

To calculate the number of moles of sulfuric acid, we need to divide the mass of sulfuric acid by its molar mass. The molar mass of sulfuric acid (H2SO4) is calculated as follows:

(2 * atomic mass of hydrogen) + atomic mass of sulfur + (4 * atomic mass of oxygen)

= (2 * 1.008 g/mol) + 32.06 g/mol + (4 * 16.00 g/mol) = 98.09 g/mol

Now, we can calculate the number of moles of sulfuric acid:

Number of moles of H2SO4 = (mass of H2SO4) / (molar mass of H2SO4) = 490 g / 98.09 g/mol = 4.999 moles (approximately 5 moles)

Step 2: Calculate the number of moles of hydrogen gas (H2)

From the balanced chemical equation, we know that 1 mole of magnesium reacts with 1 mole of sulfuric acid to produce 1 mole of hydrogen gas.

Since the number of moles of sulfuric acid is 5 moles, the number of moles of hydrogen gas produced will also be 5 moles.

Step 3: Calculate the mass of hydrogen gas (H2)

The molar mass of hydrogen (H2) is approximately 2.02 g/mol.

To calculate the mass of hydrogen gas, we can use the following formula:

Mass of H2 = (number of moles of H2) * (molar mass of H2) = 5 moles * 2.02 g/mol = 10.1 grams

Therefore, the mass of hydrogen gas that can be obtained from the reaction between magnesium and the sulfuric acid solution is approximately 10.1 grams.

Please note that the above calculation assumes ideal conditions and complete reaction conversion. In practice, the actual yield may be lower due to various factors such as side reactions and incomplete conversion.

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