Вопрос задан 09.05.2019 в 20:13. Предмет Химия. Спрашивает Ивандаев Анатолий.

ПОМОГИТЕ СРОЧНО !!!!!!!!!!!!!!!!!!!! Расставьте коэффициенты методом электронного баланса: 1) S+

HNO3 -> H2SO4+NO2+H2O ; 2) P+HNO3+H2O ->H3PO4 +NO ; Взарание огромное при огромное всем спс !!!!
0 0
Перейти к ответам

Ответы на вопрос

Внимание! Ответы на вопросы дают живые люди. Они могут содержать ошибочную информацию, заблуждения, а также ответы могут быть сгенерированы нейросетями. Будьте внимательны. Если вы уверены, что ответ неверный, нажмите кнопку "Пожаловаться" под ответом.
Отвечает Максутов Руслан.

вроде так должно быть, я прикрепила файл

0 0
Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Balancing Chemical Equations using the Electron Balance Method

To balance the given chemical equations using the electron balance method, we need to ensure that the number of atoms of each element is the same on both sides of the equation. We will start by balancing the atoms that appear in only one compound on each side of the equation and then proceed to balance the remaining atoms.

1) S + HNO3 -> H2SO4 + NO2 + H2O

Let's start by balancing the sulfur (S) atoms. There is one sulfur atom on the left side and one on the right side, so sulfur is already balanced.

Next, let's balance the nitrogen (N) atoms. There is one nitrogen atom on the left side and one on the right side, so nitrogen is also balanced.

Now, let's balance the hydrogen (H) atoms. There are three hydrogen atoms on the left side (in HNO3) and four hydrogen atoms on the right side (two in H2SO4 and two in H2O). To balance the hydrogen atoms, we can add a coefficient of 2 in front of HNO3 on the left side:

2HNO3 + S -> H2SO4 + NO2 + H2O

Finally, let's balance the oxygen (O) atoms. There are six oxygen atoms on the left side (in HNO3) and seven oxygen atoms on the right side (four in H2SO4 and three in H2O). To balance the oxygen atoms, we can add a coefficient of 3 in front of H2SO4 on the right side:

2HNO3 + S -> 3H2SO4 + NO2 + H2O

Therefore, the balanced equation is:

2HNO3 + S -> 3H2SO4 + NO2 + H2O

2) P + HNO3 + H2O -> H3PO4 + NO

Let's start by balancing the phosphorus (P) atoms. There is one phosphorus atom on the left side and one on the right side, so phosphorus is already balanced.

Next, let's balance the nitrogen (N) atoms. There is one nitrogen atom on the left side and one on the right side, so nitrogen is also balanced.

Now, let's balance the hydrogen (H) atoms. There are four hydrogen atoms on the left side (two in HNO3 and two in H2O) and four hydrogen atoms on the right side (in H3PO4). Hydrogen is already balanced.

Finally, let's balance the oxygen (O) atoms. There six oxygen atoms on the left side (in HNO3 and H2O) and five oxygen atoms on the right side (four in H3PO4 and one in NO). To balance the oxygen atoms, we can add a coefficient of 2 in front of HNO3 on the left side:

2P + 6HNO3 + 3H2O -> 2H3PO4 + NO

Therefore, the balanced equation is:

2P + 6HNO3 + 3H2O -> 2H3PO4 + NO

I hope this helps! Let me know if you have any further questions.

0 0

Топ вопросов за вчера в категории Химия

Последние заданные вопросы в категории Химия

Задать вопрос