Question

Помогите решить 2 химических уравнений 1)А1 + Fe2O3 → Fe + А12O3; 2)H2S + O2→ SO2 + H2O. Очень срочно нужно

Answer 1

2Al + Fe2O3 = 2Fe + Al2O3
2Al - 6e = 2Al(+3)            1
2Fe(+3) +6e = 2Fe          1

2H2S + 3O2 = 2SO2 + 2H2O
S(-2) - 6e = S(+4)            2
O2 + 4e = 2O(-2)             3

Answer 2

Balancing Chemical Equations

Sure, I can help you balance these chemical equations. Let's start with the first equation:

1) Al + Fe2O3 → Fe + Al2O3

To balance this equation, we need to make sure that the number of atoms of each element is the same on both sides of the equation. Here's how we can do it step by step:

Step 1: Count the number of atoms for each element on both sides of the equation.

On the left side: - Al: 1 atom - Fe: 2 atoms - O: 3 atoms

On the right side: - Fe: 1 atom - Al: 2 atoms - O: 3 atoms

Step 2: Balance the atoms of each element one by one.

Let's start with Al. Since there are 1 Al atom on the left side and 2 Al atoms on the right side, we need to put a coefficient of 2 in front of Al on the left side:

2Al + Fe2O3 → Fe + Al2O3

Now, let's balance Fe. Since there are 2 Fe atoms on the left side and 1 Fe atom on the right side, we need to put a coefficient of 2 in front of Fe on the right side:

2Al + Fe2O3 → 2Fe + Al2O3

Finally, let's balance O. Since there are 3 O atoms on both sides, the equation is already balanced.

The balanced equation is:

2Al + Fe2O3 → 2Fe + Al2O3.

Now, let's move on to the second equation:

2) H2S + O2 → SO2 + H2O

Following the same steps as before:

Step 1: Count the number of atoms for each element on both sides of the equation.

On the left side: - H: 2 atoms - S: 1 atom - O: 2 atoms

On the right side: - S: 1 atom - O: 3 atoms - H: 2 atoms

Step 2: Balance the atoms of each element one by one.

Let's start with S. Since there is 1 S atom on both sides, the S atoms are already balanced.

Next, let's balance O. Since there are 2 O atoms on the left side and 3 O atoms on the right side, we need to put a coefficient of 3/2 (or 1.5) in front of O2 on the left side:

H2S + 1.5O2 → SO2 + H2O

To get rid of the fractional coefficient, we can multiply the entire equation by 2:

2H2S + 3O2 → 2SO2 + 2H2O

Finally, let's balance H. Since there are 4 H atoms on the left side and 4 H atoms on the right side, the H atoms are already balanced.

The balanced equation is:

2H2S + 3O2 → 2SO2 + 2H2O.

I hope this helps! Let me know if you have any further questions.