Question

3Al(OH)3 + H2SO4 ---->?

Answer 1

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

Answer 2

H2SO4 + Al(OH)3 = Al(OH)SO4 + 2H2O
3H2SO4 + Al(OH)3 = Al(HSO4)3 + 3H2O
H2SO4 +2 Al(OH)3 = [Al(OH)2]2SO4 + 2H2O
3H2SO4+2Al(OH)3=Al2(SO4)3+6H2O 

Answer 3

Reaction of Aluminum Hydroxide with Sulfuric Acid

When aluminum hydroxide Al(OH)3 reacts with sulfuric acid H2SO4, the following reaction occurs:

Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

Aluminum hydroxide reacts with sulfuric acid in a acid-base neutralization reaction. Aluminum hydroxide Al(OH)3 is a base that can accept protons from the acid H2SO4. Three moles of sulfuric acid are needed to fully neutralize one mole of aluminum hydroxide since aluminum hydroxide has a basicity of 3.

The products are aluminum sulfate Al2(SO4)3 and water H2O. Aluminum sulfate is an important industrial chemical that is used as a mordant in dyeing, in water purification, and in other applications.