Question

Найти массу сульфата алюминия, если в реакцию с алюминием вступает 98 г серной кислоты.Срочно!!!

Answer 1

Дано:
m(H₂SO₄) = 98г
Найти:
m(Al₂(SO₄)₃) 
Решение:
2Al + 3H₂SO₄ = Al₂(SO₄)₃ + 3H₂
Mr(Al₂(SO₄)₃) = 342 г/моль
Mr(H₂SO₄) = 98 г/моль (по реакции 294)
m(Al₂(SO₄)₃) = $\frac{98*342}{294} =$ 114г
Ответ: m(Al₂(SO₄)₃) = 114г

Answer 2

Как-то так. Удачи тебе.)

Answer 3

Calculation of the Mass of Aluminum Sulfate

To calculate the mass of aluminum sulfate (Al2(SO4)3) formed when 98 g of sulfuric acid (H2SO4) reacts with aluminum (Al), we need to determine the stoichiometry of the reaction.

The balanced chemical equation for the reaction between sulfuric acid and aluminum is as follows:

2 Al + 3 H2SO4 → Al2(SO4)3 + 3 H2

From the balanced equation, we can see that 2 moles of aluminum react with 3 moles of sulfuric acid to produce 1 mole of aluminum sulfate.

To calculate the mass of aluminum sulfate, we need to convert the given mass of sulfuric acid (98 g) to moles using its molar mass and then use the stoichiometry of the reaction to determine the moles of aluminum sulfate formed. Finally, we can convert the moles of aluminum sulfate to grams using its molar mass.

Let's calculate the mass of aluminum sulfate step by step:

1. Calculate the moles of sulfuric acid: - The molar mass of sulfuric acid (H2SO4) is 98.09 g/mol. - Moles of sulfuric acid = mass of sulfuric acid / molar mass of sulfuric acid. - Moles of sulfuric acid = 98 g / 98.09 g/mol = 1 mol.

2. Use the stoichiometry of the reaction to determine the moles of aluminum sulfate: - From the balanced equation, we know that 2 moles of aluminum react with 1 mole of aluminum sulfate. - Therefore, moles of aluminum sulfate = (moles of sulfuric acid) / 3 * 1 / 2 = 1 mol / 3 * 1 / 2 = 1/6 mol.

3. Calculate the mass of aluminum sulfate: - The molar mass of aluminum sulfate (Al2(SO4)3) is 342.15 g/mol. - Mass of aluminum sulfate = moles of aluminum sulfate * molar mass of aluminum sulfate. - Mass of aluminum sulfate = (1/6 mol) * 342.15 g/mol = 57.03 g.

Therefore, the mass of aluminum sulfate formed when 98 g of sulfuric acid reacts with aluminum is approximately 57.03 grams.

Please note that the above calculation assumes the reaction goes to completion and there are no other limiting factors or side reactions.