Question

Степень окисления металлов в AgHSO4 ; AlPO4 ; Na2SO4

Answer 1

У серебра +1
У алюминия +3
У натрия +1

Answer 2

Степень окисления металлов в AgHSO4, AlPO4 и Na2SO4

AgHSO4: - AgHSO4 is a compound composed of silver (Ag), hydrogen (H), sulfur (S), and oxygen (O). - To determine the oxidation state of Ag in AgHSO4, we need to consider the oxidation states of the other elements in the compound. - Hydrogen (H) is typically assigned an oxidation state of +1, and oxygen (O) is typically assigned an oxidation state of -2. - Sulfur (S) is usually assigned an oxidation state of +6 in sulfate compounds. - Since the sum of the oxidation states in a compound must be zero, we can calculate the oxidation state of Ag in AgHSO4 using the following equation: Ag + H + S + 4O = 0 Ag + 1 + 6 + 4(-2) = 0 Ag + 1 + 6 - 8 = 0 Ag - 1 = 0 Ag = +1

Therefore, the oxidation state of silver (Ag) in AgHSO4 is +1.

AlPO4: - AlPO4 is a compound composed of aluminum (Al), phosphorus (P), and oxygen (O). - To determine the oxidation state of Al in AlPO4, we need to consider the oxidation states of the other elements in the compound. - Oxygen (O) is typically assigned an oxidation state of -2. - Phosphorus (P) can have various oxidation states, but in this case, it is most likely assigned an oxidation state of +5. - Since the sum of the oxidation states in a compound must be zero, we can calculate the oxidation state of Al in AlPO4 using the following equation: Al + P + 4O = 0 Al + 5 + 4(-2) = 0 Al + 5 - 8 = 0 Al - 3 = 0 Al = +3

Therefore, the oxidation state of aluminum (Al) in AlPO4 is +3.

Na2SO4: - Na2SO4 is a compound composed of sodium (Na), sulfur (S), and oxygen (O). - To determine the oxidation state of Na in Na2SO4, we need to consider the oxidation states of the other elements in the compound. - Oxygen (O) is typically assigned an oxidation state of -2. - Sulfur (S) is usually assigned an oxidation state of +6 in sulfate compounds. - Since the sum of the oxidation states in a compound must be zero, we can calculate the oxidation state of Na in Na2SO4 using the following equation: 2Na + S + 4O = 0 2Na + 6 + 4(-2) = 0 2Na + 6 - 8 = 0 2Na - 2 = 0 2Na = +2 Na = +1

Therefore, the oxidation state of sodium (Na) in Na2SO4 is +1.

Please note that the oxidation states mentioned above are based on general rules and assumptions. In some cases, the oxidation states may vary depending on the specific compound or reaction conditions.