Question

Во время спиртового брожения глюкозы получено 200г этанола з выходом 90%. Найдите масу глюкозы.

Answer 1

C6H12O6 ---> 2C2H5OH +2CO2 (спиртовое брожение)
m(чистСпирта)=0.9x200=180г
n(c2h5oh)= m /M
n(C2h5oh) = 180/46=3.91моль
по уравнению
x   ------ 3.91 моль
1   ------ 2 молбь
x-- n(C6H12O6)
x= 1x3.91 / 2 = 1,96 моль
m(C6H12O6)= 1,96x180 =352,8 Г
ответ : m(c6h12o6) =352,8 Г

Answer 2

Calculation of Glucose Mass

To find the mass of glucose used during the process of alcoholic fermentation, we can use the information provided. We know that 200g of ethanol was obtained with a yield of 90%.

To calculate the mass of glucose, we can use the following equation:

Mass of glucose = (Mass of ethanol obtained / Yield) * 100

Substituting the given values:

Mass of glucose = (200g / 0.9) * 100

Calculating this equation, we find:

Mass of glucose = 222.22g

Therefore, the mass of glucose used during the process of alcoholic fermentation is approximately 222.22 grams.