Question

Сколько граммов меди выделится на железной пластине массой 50 г, опущенной в раствор CuSO4, если в результате реакции масса пластины увеличилась на 4 г?

Answer 1

                      
CuSO4+Fe=FeSO4+CU-------

Answer 2

Calculation of Copper Deposition on Iron Plate

To calculate the amount of copper (Cu) that will be deposited on an iron (Fe) plate when it is immersed in a solution of copper sulfate (CuSO4), we need to consider the mass change of the iron plate.

Given: - Mass of the iron plate = 50 g - Increase in mass of the iron plate after the reaction = 4 g

To find the mass of copper deposited on the iron plate, we need to determine the amount of iron that has reacted with the copper sulfate solution. Since the reaction involves the transfer of electrons, we can use the concept of stoichiometry to relate the mass change of the iron plate to the mass of copper deposited.

The balanced chemical equation for the reaction between iron and copper sulfate is as follows:

Fe + CuSO4 → FeSO4 + Cu

From the balanced equation, we can see that the stoichiometric ratio between iron and copper is 1:1. This means that for every 1 mole of iron that reacts, 1 mole of copper is deposited.

To calculate the amount of copper deposited, we can use the molar mass of iron (55.845 g/mol) and copper (63.546 g/mol). Since the molar mass ratio is 1:1, the mass ratio will also be 1:1.

Therefore, the mass of copper deposited on the iron plate is equal to the increase in mass of the iron plate, which is 4 g.

Mass of copper deposited = 4 g.

Please note that this calculation assumes ideal conditions and complete conversion of reactants to products. In practice, there may be some loss or inefficiency in the reaction.

I hope this helps! Let me know if you have any further questions.