
Какой объем водорода выделится при взаимодействии с водой кальция количеством вещества 1,5 моль?
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Ответы на вопрос




Hydrogen Gas Produced from the Reaction of Calcium with Water
When calcium reacts with water, hydrogen gas is produced according to the following chemical equation:
Ca(s) + 2H2O(l) → Ca(OH)2(aq) + H2(g)
To find the volume of hydrogen gas produced when 1.5 moles of calcium react with water, we can use the ideal gas law equation:
PV = nRT
Where: - P = pressure - V = volume - n = number of moles - R = ideal gas constant - T = temperature
We can assume standard temperature and pressure (STP) conditions for this calculation, where the pressure is 1 atmosphere and the temperature is 273.15 K.
Using the molar volume of a gas at STP (22.4 L/mol), we can calculate the volume of hydrogen gas produced.
Calculation
The molar ratio of calcium to hydrogen gas in the balanced chemical equation is 1:1. This means that for every mole of calcium that reacts, 1 mole of hydrogen gas is produced.Given: - Number of moles of calcium (n) = 1.5 moles
Using the molar volume of a gas at STP: - Volume of hydrogen gas produced = 1.5 moles * 22.4 L/mol = 33.6 L
Therefore, when 1.5 moles of calcium react with water, approximately 33.6 liters of hydrogen gas will be produced


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