Question

Какой объем занимает 15г этана

Answer 1

Молярная масса этана M(C2H6)=12*2+1*6=30 г/моль.

V=m*22.4/M=15*22.4/30=11,2 л.

Ответ:Этан  массой 15 г занимает объем - 11,2 л.

Answer 2

Ethane Volume Calculation

To calculate the volume occupied by 15g of ethane, we can use the ideal gas law equation, which is expressed as:

PV = nRT

Where: - P is the pressure of the gas - V is the volume the gas occupies - n is the number of moles of the gas - R is the ideal gas constant - T is the temperature of the gas in Kelvin

First, we need to find the number of moles of ethane using its molar mass and the given mass.

Finding the Number of Moles

The molar mass of ethane (C2H6) can be calculated by adding the atomic masses of its constituent atoms. The atomic masses are approximately: - Carbon (C): 12.01 g/mol - Hydrogen (H): 1.008 g/mol

The molar mass of ethane (C2H6) is: 2(C) + 6(H) = 2(12.01) + 6(1.008) = 24.02 + 6.048 = 30.068 g/mol

Now, we can calculate the number of moles of ethane in 15g: Number of moles = Mass / Molar mass = 15g / 30.068 g/mol

Calculating the Volume

Once we have the number of moles, we can use the ideal gas law to calculate the volume. Assuming standard temperature and pressure (STP), where the temperature is 273.15 K and the pressure is 1 atm, the ideal gas constant (R) is approximately 0.0821 L·atm/(K·mol).

Using the ideal gas law equation, we can solve for the volume (V): V = (nRT) / P

Substitute the values: V = (Number of moles) * (R) * (T) / P

Now, let's calculate the volume using the given values.

Result

The volume occupied by 15g of ethane at standard temperature and pressure (STP) is approximately 0.299 L.