Question

Какое количество вещества гидроксида натрия требуется для полной нейтрализации серной кислоты количеством вещества 0.25 моль

Answer 1

2NaOH+H2SO4=Na2SO4+2H2O
По уравнению: 2 моль NaOH - 1 моль H2SO4
По условию:     Х моль NaOH - 0,25 моль H2SO4
Х= 2 моль*0,25 моль/ 1 моль=0,5 моль

Answer 2

Calculating the Amount of Sodium Hydroxide Needed to Neutralize Sulfuric Acid

To calculate the amount of sodium hydroxide (NaOH) needed to neutralize sulfuric acid (H2SO4), we can use the balanced chemical equation for the neutralization reaction between NaOH and H2SO4:

H2SO4 + 2NaOH → Na2SO4 + 2H2O

From the balanced equation, we can see that 1 mole of sulfuric acid reacts with 2 moles of sodium hydroxide.

Given that the amount of substance of sulfuric acid is 0.25 moles, we can calculate the amount of sodium hydroxide required for complete neutralization.

Calculation

Using the stoichiometry of the balanced chemical equation, we can determine the amount of sodium hydroxide needed:

1 mole of H2SO4 reacts with 2 moles of NaOH.

Therefore, the amount of NaOH required can be calculated as follows:

0.25 moles H2SO4 × (2 moles NaOH / 1 mole H2SO4) = 0.5 moles NaOH

So, 0.5 moles of sodium hydroxide are required to completely neutralize 0.25 moles of sulfuric acid.

[[9 #]] provides the stoichiometry information for the reaction between sulfuric acid and sodium hydroxide, confirming the calculation.