Question

Сколько грамм соляной кислоты потребуется для взаимодействия с 7 граммами цинка решение

Answer 1

Zn + hcl -> zncl2 + h2
Моль цинк = 7/64= 0,109375
Моль hcl = тоже 0,109375
Значит найдем массу соляной кислоты 0,109375 * 36,5 тогда выходит 3,99 г 4 г

Answer 2

Calculating the Amount of Hydrochloric Acid Needed to React with Zinc

To calculate the amount of hydrochloric acid (HCl) needed to react with 7 grams of zinc (Zn), we can use the balanced chemical equation for the reaction between hydrochloric acid and zinc:

Zn + 2HCl → ZnCl2 + H2

According to the balanced chemical equation, 1 mole of zinc reacts with 2 moles of hydrochloric acid. We can use this information to calculate the amount of hydrochloric acid needed to react with 7 grams of zinc.

Calculation Steps:

1. Convert grams of zinc to moles: - The molar mass of zinc (Zn) is approximately 65.38 g/mol. - Using the formula: moles = mass / molar mass, we can calculate the moles of zinc.

2. Use mole ratio from the balanced equation: - According to the balanced equation, 1 mole of zinc reacts with 2 moles of hydrochloric acid.

3. Convert moles of hydrochloric acid to grams: - The molar mass of hydrochloric acid (HCl) is approximately 36.46 g/mol. - Using the formula: mass = moles × molar mass, we can calculate the mass of hydrochloric acid needed.

Calculation:

1. Convert grams of zinc to moles: - Molar mass of zinc (Zn) ≈ 65.38 g/mol. - Moles of zinc = 7 g / 65.38 g/mol ≈ 0.107 moles of zinc.

2. Use mole ratio from the balanced equation: - According to the balanced equation, 1 mole of zinc reacts with 2 moles of hydrochloric acid. - Moles of hydrochloric acid needed = 0.107 moles of zinc × (2 moles of HCl / 1 mole of Zn) ≈ 0.214 moles of HCl.

3. Convert moles of hydrochloric acid to grams: - Molar mass of hydrochloric acid (HCl) ≈ 36.46 g/mol. - Mass of hydrochloric acid needed = 0.214 moles of HCl × 36.46 g/mol ≈ 7.8 grams of HCl.

Therefore, approximately 7.8 grams of hydrochloric acid will be needed to react with 7 grams of zinc.