Question

Какое количество вещества занимает силан SiH4 объемом 25.67л при н.у.

Answer 1

Дано:
V(SiH4)=25.67 л
n(SiH4)-?
n=V/Vm
n(SiH4) = 25,67 л/22,4 л/моль = 1,146 моль
Ответ: 1,146 моль

Answer 2

Дано:
V(SiH4) = 25,67 л
Найти:
n(SiH4) - ?
Решение:
n(SiH4) = V / Vm = 25,67 л / 22,4 л/моль = 1,14 моль
Ответ: 1,14 моль

Answer 3

Calculating the Molar Volume of Silane (SiH4) at Standard Temperature and Pressure (STP)

To calculate the amount of substance (in moles) occupied by a given volume of silane (SiH4) at standard temperature and pressure (STP), we can use the ideal gas law equation:

PV = nRT

Where: - P = pressure - V = volume - n = amount of substance (in moles) - R = ideal gas constant - T = temperature

At STP, the conditions are: - Pressure (P) = 1 atmosphere (atm) - Temperature (T) = 273.15 Kelvin (K)

First, let's calculate the molar volume of any gas at STP using the ideal gas law equation.

Calculating the Molar Volume at STP

Using the ideal gas law equation, we can rearrange it to solve for the molar volume (V_m) at STP: V_m = (RT)/P

Where: - R = 0.0821 L·atm/(K·mol) (ideal gas constant)

Substituting the values: V_m = (0.0821 L·atm/(K·mol)) * 273.15 K / 1 atm V_m ≈ 22.4 L/mol

So, the molar volume of any gas at STP is approximately 22.4 liters per mole.

Calculating the Amount of Substance of Silane (SiH4) at 25.67 L and STP

Now, let's calculate the amount of substance (in moles) of silane (SiH4) that occupies a volume of 25.67 liters at STP.

Using the molar volume at STP, we can calculate the amount of substance: n = V / V_m

Where: - V = volume of silane (SiH4) = 25.67 L - V_m = molar volume at STP = 22.4 L/mol

Substituting the values: n = 25.67 L / 22.4 L/mol n ≈ 1.147 moles

Therefore, the amount of substance of silane (SiH4) occupying a volume of 25.67 liters at STP is approximately 1.147 moles.

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