Question

Уравнение реакций (краткое и полное ионное)1) Al2(SO4)3 + BaCl2 2) Al2(SO4)3 + NaOH 3) Al(OH)3 + NaOH (без ионной формы)

Answer 1

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Answer 2

1) Al2(SO4)3 + 3 BaCl2 => 2AlCl3 + 3 BaSO4↓ 3Ba(2+) + 3SO4(2-) => 3 BaSO4↓ 2) Al2(SO4)3 + 6NaOH=> 2Al(OH)3↓ + 3Na2SO4 2Al(3+) + 6OH(-) => Al(OH)3↓ 3) 2Al(OH)3 +NaOH => Na[Al(OH)4] 2Al(OH)3 +OH(-) => [Al(OH)4](-)

Answer 3

Balancing Chemical Equations

1) Balancing the Equation: Al2(SO4)3 + BaCl2

The balanced chemical equation for the reaction between aluminum sulfate and barium chloride is as follows:

Short Form: Al2(SO4)3 + 3BaCl2 → 2AlCl3 + 3BaSO4

Ionic Form: 2Al^3+ + 3SO4^2- + 3Ba^2+ + 6Cl^- → 2Al^3+ + 6Cl^- + 3Ba^2+ + 3SO4^2-

2) Balancing the Equation: Al2(SO4)3 + NaOH

The balanced chemical equation for the reaction between aluminum sulfate and sodium hydroxide is as follows:

Short Form: Al2(SO4)3 + 6NaOH → 2Al(OH)3 + 3Na2SO4

Ionic Form: 2Al^3+ + 3SO4^2- + 6Na^+ +