Question

Расставьте коэффициенты в уравнениях окислительно-восстановительных реакций1)Fe+Cl2-->FeCl32)HBr+H2SO4-->SO2+Br2+H2O3)Na2SO3+K2Cr2O7+H2SO4-->Cr2(SO4)3+Na2SO4+K2SO4+H2O4)AgNO3-->Ag+NO2+O25)P+H2o-->H3PO3+PH3Заранее благодарен))))

Answer 1

1)2Fe+3Cl2-->2FeCl3

2) 2HBr+H2SO4-->Br2+SO2+2H2O

3)3Na2SO3+K2Cr2O7+4H2SO4-->Cr2(SO4)3+3Na2SO4+K2SO4+4H2O

4)2AgNO3-->2Ag+2NO2+O2

5)2P+8H2o-->2H3PO3+5H2

 

 

 

 

 

 

Answer 2

Balancing Redox Equations

To balance the given redox equations, we need to assign oxidation numbers to each element in the reactants and products and then balance the atoms and charges on both sides of the equation. Here are the balanced equations for the given reactions:

1) Fe + Cl2 -> FeCl3

To balance this equation, we need to assign oxidation numbers to Fe and Cl. The oxidation number of Fe changes from 0 to +3, and the oxidation number of Cl changes from 0 to -1.

The balanced equation is:

2 Fe + 3 Cl2 -> 2 FeCl3 [[1]]

2) HBr + H2SO4 -> SO2 + Br2 + H2O

To balance this equation, we need to assign oxidation numbers to H, Br, S, and O. The oxidation number of Br changes from -1 to 0, and the oxidation number of S changes from +6 to +4.

The balanced equation is:

8 HBr + H2SO4 -> SO2 + 4 Br2 + 7 H2O [[2]]

3) Na2SO3 + K2Cr2O7 + H2SO4 -> Cr2(SO4)3 + Na2SO4 + K2SO4 + H2O

To balance this equation, we need to assign oxidation numbers to Na, S, Cr, and O. The oxidation number of S changes from +4 to +6, and the oxidation number of Cr changes from +6 to +3.

The balanced equation is:

3 Na2SO3 + K2Cr2O7 + 4 H2SO4 -> Cr2(SO4)3 + Na2SO4 + K2SO4 + 4 H2O [[3]]

4) AgNO3 -> Ag + NO2 + O2

To balance this equation, we need to assign oxidation numbers to Ag, N, and O. The oxidation number of Ag changes from +1 to 0, and the oxidation number of N changes from +5 to +4.

The balanced equation is:

2 AgNO3 -> 2 Ag + 2 NO2 + O2 [[4]]

5) P + H2O -> H3PO3 + PH3

To balance this equation, we need to assign oxidation numbers to P and H. The oxidation number of P changes from 0 to +3, and the oxidation number of H changes from +1 to -1.

The balanced equation is:

4 P + 3 H2O -> 2 H3PO3 + PH3 [[5]]

I hope this helps! Let me know if you have any further questions.