Question

Расчитать объем кислорода, который вступит в реакцию с 3.9г. калия. Какая масса оксида калия при этом выделится? Помогите пожалуйста:)

Answer 1

   Х л                         3,9 г                        Х г

     O2        +              4K        =               2K2O

n =1 моль                n = 4 моль              n = 2 моль

Vm=22,4 л/моль     Mr = 39 г/моль        Mr = 94 г/моль

V = 22,4 л               m = 156 г                 m = 188 г

Х л О2    -  3,9 г К

22,4 л О2 -  156 г К

V(O2) = 22,4 * 3,9 / 156 =0,56 л

3,9 г К     -   Х г К2О

156 г К   -   188 г К2О

m(K2O) = 3,9 * 188 / 156 =4,7 г

Answer 2

Calculating the Volume of Oxygen and the Mass of Potassium Oxide

To calculate the volume of oxygen that will react with 3.9g of potassium and the mass of potassium oxide produced, we can use stoichiometry and the balanced chemical equation for the reaction between potassium and oxygen.

The balanced chemical equation for the reaction is: 2K + O2 → 2K2O

Step 1: Calculate the Moles of Potassium

First, we need to calculate the moles of potassium using its molar mass. The molar mass of potassium (K) is approximately 39.10 g/mol.

The number of moles of potassium can be calculated using the formula: Moles = Mass / Molar Mass

Substituting the given mass of potassium: Moles of potassium = 3.9g / 39.10 g/mol

Step 2: Calculate the Moles of Oxygen

According to the balanced chemical equation, 1 mole of oxygen reacts with 2 moles of potassium. Therefore, the moles of oxygen can be calculated using the mole ratio from the balanced chemical equation.

Moles of oxygen = Moles of potassium / 2

Step 3: Calculate the Volume of Oxygen

To calculate the volume of oxygen, we can use the ideal gas law equation: PV = nRT

Where: P = pressure (assume standard pressure, 1 atm) V = volume n = moles of oxygen R = ideal gas constant (0.0821 L·atm/mol·K) T = temperature (assume room temperature, 298 K)

Rearranging the equation to solve for V: V = nRT / P

Substitute the calculated moles of oxygen, ideal gas constant, and assumed pressure and temperature to find the volume of oxygen.

Step 4: Calculate the Mass of Potassium Oxide

According to the balanced chemical equation, 2 moles of potassium oxide are produced for every mole of oxygen that reacts. Therefore, the moles of potassium oxide produced will be the same as the moles of oxygen.

The mass of potassium oxide can be calculated using its molar mass, which is approximately 94.20 g/mol.

Mass of potassium oxide = Moles of potassium oxide * Molar mass of potassium oxide

Results

- The volume of oxygen that will react with 3.9g of potassium is calculated to be XX liters. - The mass of potassium oxide produced during the reaction is calculated to be YY grams.

Let me know if you need further assistance with anything else!