Question

Смесь, состоящую из 1,48 г гидроксида кальция и 3 г сульфата аммония, нагрели до прекращения реакции. Сколько аммиака при этом образовалось?

Answer 1

Дано:                                    Решение
m (Ca(OH)2) = 1.48 г              1.48г           3г                                     х моль

m ((NH4)2SO4) = 3 г            Ca(OH)2+(NH4)2SO4---> CaSO4+ 2NH3+2H2O

V (NH3) = ?                                74г             132г                                22,4моль

 

                                                 1) m (Ca(OH)2) = 74 грамм

                                                 2) m ( NH4)2SO4 = 132 грамм

3) V1 = 1.48/74=0.02 моль

4) V2 = 3/132=0.02 моль 

так как V1 = V2 =>

5) Пропорция: 3/132 = х/22,4

х= (3*22,4)/132 = 0,5 моль.

 

Ответ: V( NH3) = 0,5 моль 

Answer 2

Chemical Reaction and Calculation

To calculate the amount of ammonia formed when a mixture consisting of 1.48g of calcium hydroxide and 3g of ammonium sulfate is heated until the reaction stops, we can use the following chemical equation:

Ca(OH)2 + (NH4)2SO4 → CaSO4 + 2NH3 + 2H2O

First, we need to determine the limiting reactant to find out how much ammonia is formed.

The molar masses of the compounds are: - Ca(OH)2: 74.09 g/mol - (NH4)2SO4: 132.14 g/mol

The number of moles of each compound can be calculated using the given masses: - Moles of Ca(OH)2 = 1.48g / 74.09 g/mol - Moles of (NH4)2SO4 = 3g / 132.14 g/mol

Let's calculate the moles of each compound and determine the limiting reactant.

Calculation of Moles and Limiting Reactant

Moles of Ca(OH)2: - Moles of Ca(OH)2 = 1.48g / 74.09 g/mol = 0.02 moles

Moles of (NH4)2SO4: - Moles of (NH4)2SO4 = 3g / 132.14 g/mol = 0.02 moles

Since the stoichiometric coefficient of Ca(OH)2 is 1 and that of (NH4)2SO4 is also 1, both compounds are present in equal moles. Therefore, the limiting reactant is Ca(OH)2.

Calculation of Ammonia Formed

From the balanced chemical equation, 1 mole of Ca(OH)2 produces 2 moles of NH3. Therefore, the moles of NH3 formed will be twice the moles of Ca(OH)2 used.

Moles of NH3 formed = 2 * Moles of Ca(OH)2 = 2 * 0.02 moles = 0.04 moles

Conclusion

When the given mixture is heated until the reaction stops, 0.04 moles of ammonia are formed.