Question

В реакцию вступило 300гр. силиката магния и соляная кислота. Найдите количество вещества получившейся кремниевой кислоты. Пожалуйста помогите химия 8 кл.

Answer 1

1) MgSiO3+2HCl=MgCl2+H2SiO3
2) n( MgSiO3)= 300гр/ 100гр/моль=3моль
3) n (H2SiO3)=n(MgSiO3)=3моль

Answer 2

Chemical Reaction Calculation

To calculate the amount of siliconic acid produced from the reaction of 300g of magnesium silicate and hydrochloric acid, we can use the balanced chemical equation for the reaction and the concept of stoichiometry.

The balanced chemical equation for the reaction between magnesium silicate and hydrochloric acid is:

Mg2SiO4 + 4HCl → 2MgCl2 + H4SiO4

From the balanced equation, we can see that 1 mole of magnesium silicate reacts with 4 moles of hydrochloric acid to produce 1 mole of siliconic acid.

Calculation Steps

1. Calculate the moles of magnesium silicate: - The molar mass of magnesium silicate (Mg2SiO4) is approximately 120.366 g/mol. - Number of moles = Mass / Molar mass - Number of moles = 300g / 120.366 g/mol

2. Use the mole ratio from the balanced equation to find the moles of siliconic acid produced: - According to the balanced equation, 1 mole of magnesium silicate produces 1 mole of siliconic acid. - Therefore, the moles of siliconic acid produced will be the same as the moles of magnesium silicate used in the reaction.

Calculation Result

By following these steps, you can calculate the amount of siliconic acid produced from the given reaction. If you need further assistance with the calculations, feel free to ask!