Question

Помогите пожалуйста решить задачи 1)Расчитайте количество вещества и массу 0,6*10в23 молекул фосфорной кислоты H3PO4. 2) Сколько молекул и моль содержится в 28,4 г оксида фосфора (V) P2O5 Заранее большое спасибо!!

Answer 1

2) 24.2 28342124921 P205 (V)

Answer 2

Calculation of the Amount of Substance and Mass of Phosphoric Acid (H3PO4)

To calculate the amount of substance and mass of 0.6 * 10^23 molecules of phosphoric acid (H3PO4), we need to use Avogadro's number and the molar mass of H3PO4.

1. The molar mass of H3PO4 can be calculated by adding up the atomic masses of its constituent elements: - Atomic mass of hydrogen (H) = 1.00784 g/mol - Atomic mass of phosphorus (P) = 30.97376 g/mol - Atomic mass of oxygen (O) = 15.999 g/mol

Therefore, the molar mass of H3PO4 is: (3 * 1.00784 g/mol) + (1 * 30.97376 g/mol) + (4 * 15.999 g/mol) = 97.995 g/mol.

2. To calculate the amount of substance (in moles) of 0.6 * 10^23 molecules of H3PO4, we can use the following formula: Amount of substance (in moles) = Number of molecules / Avogadro's number.

Avogadro's number is approximately 6.022 * 10^23 molecules/mol.

Therefore, the amount of substance of 0.6 * 10^23 molecules of H3PO4 is: (0.6 * 10^23 molecules) / (6.022 * 10^23 molecules/mol) = 0.0996 mol.

3. To calculate the mass of 0.6 * 10^23 molecules of H3PO4, we can use the following formula: Mass = Amount of substance * Molar mass.

Therefore, the mass of 0.6 * 10^23 molecules of H3PO4 is: 0.0996 mol * 97.995 g/mol = 9.76 g.

Therefore, the amount of substance of 0.6 * 10^23 molecules of phosphoric acid (H3PO4) is approximately 0.0996 mol, and the mass is approximately 9.76 g.

Calculation of the Number of Molecules and Moles in 28.4 g of Phosphorus Pentoxide (P2O5)

To calculate the number of molecules and moles in 28.4 g of phosphorus pentoxide (P2O5), we need to use Avogadro's number and the molar mass of P2O5.

1. The molar mass of P2O5 can be calculated by adding up the atomic masses of its constituent elements: - Atomic mass of phosphorus (P) = 30.97376 g/mol - Atomic mass of oxygen (O) = 15.999 g/mol

Therefore, the molar mass of P2O5 is: (2 * 30.97376 g/mol) + (5 * 15.999 g/mol) = 141.944 g/mol.

2. To calculate the amount of substance (in moles) of 28.4 g of P2O5, we can use the following formula: Amount of substance (in moles) = Mass / Molar mass.

Therefore, the amount of substance of 28.4 g of P2O5 is: 28.4 g / 141.944 g/mol = 0.2 mol.

3. To calculate the number of molecules in 28.4 g of P2O5, we can use the following formula: Number of molecules = Amount of substance * Avogadro's number.

Therefore, the number of molecules in 28.4 g of P2O5 is: 0.2 mol * 6.022 * 10^23 molecules/mol = 1.204 * 10^23 molecules.

Therefore, in 28.4 g of phosphorus pentoxide (P2O5), there are approximately 1.204 * 10^23 molecules and 0.2 mol.

I hope this helps! Let me know if you have any further questions.