Question

Определите, какой объем углекислого газа (н.у,) выделится при взаимодействии 15 г карбоната натрия,содержащего 15%примесей с соляной кислотой

Answer 1

Na2CO3+HCl=2NaCl+H2O+CO2

m(Na2CO3)=15*0,85=12.75

n=12.75\(46+12+48)=0.12

v(CO2)=0.12*22.4=2,7л 

Answer 2

Na2CO3 + 2HCl = 2NaCl + H2O + CO2

m(Na2CO3чист)=15*0.85=12.75г

M(Na2CO3)=106г/моль

n(Na2CO3)=12.75/106=0.12моль =>n(CO2)=0.12моль

V(CO2)=Vm*n=22.4*0.12=2.69л

Answer 3

Calculation of the Volume of Carbon Dioxide Gas Released

To determine the volume of carbon dioxide gas released when 15 grams of sodium carbonate reacts with hydrochloric acid, we need to use the balanced chemical equation for the reaction. The balanced equation for the reaction between sodium carbonate (Na2CO3) and hydrochloric acid (HCl) is as follows:

Na2CO3 + 2HCl → 2NaCl + H2O + CO2

According to the balanced equation, one mole of sodium carbonate reacts with two moles of hydrochloric acid to produce one mole of carbon dioxide gas. To calculate the volume of carbon dioxide gas released, we need to convert the mass of sodium carbonate to moles and then use the mole ratio from the balanced equation.

1. Calculate the number of moles of sodium carbonate: - The molar mass of sodium carbonate (Na2CO3) is 105.99 g/mol. - Therefore, the number of moles of sodium carbonate is calculated as follows: moles of Na2CO3 = mass of Na2CO3 / molar mass of Na2CO3 moles of Na2CO3 = 15 g / 105.99 g/mol

2. Use the mole ratio from the balanced equation to determine the number of moles of carbon dioxide gas produced: - According to the balanced equation, one mole of sodium carbonate produces one mole of carbon dioxide gas. - Therefore, the number of moles of carbon dioxide gas produced is the same as the number of moles of sodium carbonate.

3. Convert the number of moles of carbon dioxide gas to volume at standard temperature and pressure (STP): - At STP, one mole of any gas occupies 22.4 liters. - Therefore, the volume of carbon dioxide gas released is calculated as follows: volume of CO2 = moles of CO2 * 22.4 L/mol

Now, let's calculate the volume of carbon dioxide gas released.

Calculation:

1. Calculate the number of moles of sodium carbonate: - The molar mass of sodium carbonate (Na2CO3) is 105.99 g/mol. - Therefore, the number of moles of sodium carbonate is calculated as follows: moles of Na2CO3 = 15 g / 105.99 g/mol = 0.1414 mol

2. Use the mole ratio from the balanced equation to determine the number of moles of carbon dioxide gas produced: - According to the balanced equation, one mole of sodium carbonate produces one mole of carbon dioxide gas. - Therefore, the number of moles of carbon dioxide gas produced is the same as the number of moles of sodium carbonate: moles of CO2 = 0.1414 mol

3. Convert the number of moles of carbon dioxide gas to volume at standard temperature and pressure (STP): - At STP, one mole of any gas occupies 22.4 liters. - Therefore, the volume of carbon dioxide gas released is calculated as follows: volume of CO2 = 0.1414 mol * 22.4 L/mol = 3.17 liters

Therefore, approximately 3.17 liters of carbon dioxide gas (at STP) will be released when 15 grams of sodium carbonate reacts with hydrochloric acid.