Question

Какой объем воздуха потребуется для окисления 220 г угля? Объем для кислорода 21%

Answer 1

С+О2=СО2
 На окисление 1 моль угля (12 грамм) требуется 22,4 литра кислорода
количество угля 220/12=18,33 моль
Объем кислорода 18,33*22,4=410,67л
этот объем - 21% от всего объема воздуха, значит воздуха надо 410,67*100%/21%=1955,56 литров

Answer 2

Calculating Air Volume Required for Coal Oxidation

To calculate the volume of air required for the oxidation of 220g of coal, we can use the stoichiometry of the reaction between coal and oxygen. The balanced chemical equation for the combustion of coal can be represented as:

C + O2 → CO2

From the balanced equation, we can see that 1 mole of carbon (C) reacts with 1 mole of oxygen (O2) to produce 1 mole of carbon dioxide (CO2).

Calculation Steps

1. Calculate the moles of coal (C) using its molar mass. 2. Use the stoichiometry of the reaction to find the moles of oxygen (O2) required. 3. Convert the moles of oxygen to volume using the ideal gas law.

Calculation Details

1. Moles of Coal (C): - The molar mass of carbon (C) is approximately 12.01 g/mol. - Therefore, the moles of carbon in 220g of coal can be calculated as: ``` moles of C = mass of coal / molar mass of C = 220g / 12.01 g/mol ≈ 18.32 moles ```

2. Moles of Oxygen (O2) Required: - From the balanced chemical equation, 1 mole of carbon requires 1 mole of oxygen. - Therefore, the moles of oxygen required will be the same as the moles of carbon, which is approximately 18.32 moles.

3. Volume of Oxygen (O2) Required: - Using the ideal gas law, the volume of oxygen required can be calculated as: ``` V = nRT/P where, V = volume of gas (in liters) n = moles of gas R = ideal gas constant (0.0821 L.atm/mol.K) T = temperature (in Kelvin) P = pressure (in atm)

Assuming standard temperature and pressure (STP): T = 273.15 K P = 1 atm

Therefore, V = 18.32 moles * 0.0821 L.atm/mol.K * 273.15 K / 1 atm ≈ 418.5 liters ```

Conclusion: The volume of air required for the oxidation of 220g of coal is approximately 418.5 liters.