Question

Рассчитайте массу карбида алюминия A1 4C3, который необходим для получения 5,04 л метана / объем приведён к нормальным условиям/ , если массовая доля выхода метана равна 80%

Answer 1

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Answer 2

Calculating the Mass of Aluminum Carbide (Al4C3) Required to Produce 5.04 L of Methane at Standard Conditions

To calculate the mass of aluminum carbide (Al4C3) required to produce 5.04 L of methane at standard conditions, we can use the stoichiometry of the reaction between aluminum carbide and water to produce methane.

The balanced chemical equation for the reaction is: Al4C3 + 12H2O → 4Al(OH)3 + 3CH4

From the balanced equation, we can see that 1 mole of aluminum carbide (Al4C3) reacts with 12 moles of water to produce 3 moles of methane (CH4).

Given that the molar volume of any gas at standard conditions (0°C and 1 atm) is approximately 22.4 L, we can use the ideal gas law to convert the volume of methane to moles.

Using the ideal gas law: PV = nRT Where: - P = pressure (1 atm) - V = volume (5.04 L) - n = number of moles - R = ideal gas constant (0.0821 L·atm/mol·K) - T = temperature in Kelvin (273 K at standard conditions)

We can calculate the number of moles of methane produced.

n = PV/RT = (1 atm * 5.04 L) / (0.0821 L·atm/mol·K * 273 K) n ≈ 0.223 moles of CH4

Now, using the stoichiometry of the reaction, we can calculate the moles of aluminum carbide required to produce 0.223 moles of methane.

From the balanced chemical equation, 1 mole of aluminum carbide produces 3 moles of methane. Therefore, the moles of aluminum carbide required is: 0.223 moles of CH4 * (1 mole of Al4C3 / 3 moles of CH4) ≈ 0.0743 moles of Al4C3

Finally, we can calculate the mass of aluminum carbide required using its molar mass.

The molar mass of aluminum carbide (Al4C3) is: 4(27) + 3(12) = 108 + 36 = 144 g/mol

Therefore, the mass of aluminum carbide required is: 0.0743 moles * 144 g/mol ≈ 10.68 grams of Al4C3

So, the mass of aluminum carbide (Al4C3) required to produce 5.04 L of methane at standard conditions is approximately 10.68 grams.

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