Question

ПОМОГИТЕ ПОЖАЛУЙСТА, БУДУ ОЧЕНЬ ВАМ БЛАГОДРАНА Расставьте коэффициенты в уравнениях реакций:1) P + O2 = P2O52) CH4 = C + H23) Al + HBr = AlBr3 + H24) KclO3 = Kcl + H25) Al + CuO = Al2O3 + Cu 6) CO + O = CO27) K + Hcl = Kcl + H28) BaCO3 = BaO + CO29) Ca + O2 = CaO10) H2 + Y2 = HY

Answer 1

1)4P+5O2=2P2O5 2)CH4=C+2H2 3)2Al+6HBr=2AlBr3+3H2 4)2KClO3=2KCl+3O2 5)2Al+3CuO=Al2O3+3Cu 6)2CO+O2=2CO2 7)2K+2HCl=2KCl+H2 8)BaCO3=BaO+CO2 9)2Ca+O2=2CaO 10)H2+Y2=2HY

Answer 2

1) 4P + 5O2 = 2P2O5
2) CH4 = C + 2H2
3) 2Al + 6HBr = 2AlBr3 + 3H2
4) 2KСlO3 = 2KСl + 3O2
5) 2Al + 3CuO = Al2O3 + 3Cu 
6) 2CO + O2 = 2CO2
7) 2K + 2HCl = 2KCl + H2
8) BaCO3 = BaO + CO2
9) 2Ca + O2 = 2CaO
10) H2 + I2 = 2HI

Answer 3

1) P + O2 = P2O5 2) CH4 = C + H2 3) Al + HBr = AlBr3 + H2 4) KClO3 = KCl + O2 5) Al + CuO = Al2O3 + Cu 6) CO + O2 = CO2 7) K + HCl = KCl + H2 8) BaCO3 = BaO + CO2 9) Ca + O2 = CaO 10) H2 + Y2 = HY

Let's break down each equation and identify the coefficients:

1) P + O2 = P2O5

In this equation, we have one atom of phosphorus (P) reacting with one molecule of oxygen (O2) to form one molecule of phosphorus pentoxide (P2O5). The balanced equation would be:

4P + 5O2 = 2P2O5

2) CH4 = C + H2

In this equation, we have one molecule of methane (CH4) decomposing into one atom of carbon (C) and two molecules of hydrogen gas (H2). The balanced equation would be:

CH4 = C + 2H2

3) Al + HBr = AlBr3 + H2

In this equation, we have one atom of aluminum (Al) reacting with one molecule of hydrogen bromide (HBr) to form one molecule of aluminum bromide (AlBr3) and one molecule of hydrogen gas (H2). The balanced equation would be:

2Al + 6HBr = 2AlBr3 + 3H2

4) KClO3 = KCl + O2

In this equation, we have one molecule of potassium chlorate (KClO3) decomposing into one molecule of potassium chloride (KCl) and one molecule of oxygen gas (O2). The balanced equation would be:

2KClO3 = 2KCl + 3O2

5) Al + CuO = Al2O3 + Cu

In this equation, we have one atom of aluminum (Al) reacting with one molecule of copper oxide (CuO) to form one molecule of aluminum oxide (Al2O3) and one atom of copper (Cu). The balanced equation would be:

2Al + 3CuO = Al2O3 + 3Cu

6) CO + O2 = CO2

In this equation, we have one molecule of carbon monoxide (CO) reacting with one molecule of oxygen gas (O2) to form one molecule of carbon dioxide (CO2). The balanced equation would be:

2CO + O2 = 2CO2

7) K + HCl = KCl + H2

In this equation, we have one atom of potassium (K) reacting with one molecule of hydrochloric acid (HCl) to form one molecule of potassium chloride (KCl) and one molecule of hydrogen gas (H2). The balanced equation would be:

2K + 2HCl = 2KCl + H2

8) BaCO3 = BaO + CO2

In this equation, we have one molecule of barium carbonate (BaCO3) decomposing into one molecule of barium oxide (BaO) and one molecule of carbon dioxide (CO2). The balanced equation would be:

BaCO3 = BaO + CO2

9) Ca + O2 = CaO

In this equation