Question

Определите массу образовавшегося А) бутена Б) водорода Если в реакцию дегидрирования вступило 174 г бутана

Answer 1

              174 г                                       Х г                            Х г
     CH3-CH2-CH2-CH3     ->      CH2=CH-CH2-CH3    +    H2
n=1 моль                                   n=1 моль                        n=1 моль
М = 58 г/моль                           М = 56 г/моль                 М = 2г/моль
m=58 г                                       m=56 г                            m=2 г

174 г С4Н10    -    Х г С4Н8
58 г С4Н10     -     56 г С4Н8
m(C4H8) = 174 * 56 / 58 = 168 г

174 г С4Н10    -    Х г Н2
58 г С4Н10     -    2 г Н2
m(H2) = 174 * 2 / 58 = 6 г

Answer 2

Reaction and Calculation

To determine the mass of the formed butene and hydrogen in the dehydrogenation reaction, we can use the balanced chemical equation for the reaction and the given mass of butane.

The dehydrogenation reaction of butane can be represented as: ``` C4H10 → C4H8 + H2 ```

Given that 174 g of butane is used in the reaction, we need to calculate the masses of butene and hydrogen formed.

Calculation of Butene and Hydrogen Masses

The molar mass of butane (C4H10) is 58.12 g/mol, and the molar mass of butene (C4H8) is 56.11 g/mol. The molar mass of hydrogen (H2) is 2.02 g/mol.

Using the molar ratios from the balanced chemical equation, we can calculate the masses of butene and hydrogen formed.

The molar ratio of butane to butene is 1:1, and the molar ratio of butane to hydrogen is 1:1.

Given that the molar mass of butane is 58.12 g/mol, we can calculate the moles of butane: ``` moles of butane = mass of butane / molar mass of butane = 174 g / 58.12 g/mol ≈ 2.99 moles ```

From the balanced chemical equation, we can see that for every mole of butane, 1 mole of butene and 1 mole of hydrogen are formed.

Therefore, the moles of butene formed will be equal to the moles of butane used, which is approximately 2.99 moles.

Similarly, the moles of hydrogen formed will also be approximately 2.99 moles.

To find the masses of butene and hydrogen formed, we can use the molar masses: ``` mass of butene = moles of butene * molar mass of butene ≈ 2.99 moles * 56.11 g/mol ≈ 167.67 g

mass of hydrogen = moles of hydrogen * molar mass of hydrogen ≈ 2.99 moles * 2.02 g/mol ≈ 6.04 g ```

Conclusion

Therefore, the mass of butene formed is approximately 167.67 g, and the mass of hydrogen formed is approximately 6.04 g.