Question

Написать уравнения реакции взаимодействия сульфата меди (2) и гидроксид натрия в полной и сокращенной ионной формах

Answer 1

CuSO4 + 2NaOH = Cu(OH)2 + Na2SO4 (молекулярное уравнение)
Cu(2+) + SO4(2-) + 2Na(+) + 2OH(-) = Cu(OH)2 + 2Na(+) + SO4(2-) (полное ионное)
Cu(2+) + 2OH(-) = Cu(OH)2 (сокращенное ионное)

Answer 2

Writing the Ionic Equation for the Reaction between Copper(II) Sulfate and Sodium Hydroxide

When copper(II) sulfate reacts with sodium hydroxide, it forms copper(II) hydroxide and sodium sulfate. The balanced ionic equation for this reaction can be written as follows:

Complete Ionic Equation: Cu^2+(aq) + SO4^2-(aq) + 2Na^+(aq) + 2OH^-(aq) → Cu(OH)2(s) + 2Na^+(aq) + SO4^2-(aq)

Simplified Ionic Equation: Cu^2+(aq) + 2OH^-(aq) → Cu(OH)2(s)

The reaction involves the formation of a precipitate, which is copper(II) hydroxide.