Question

Құрамында 85.7% көміртек бар азот бойынша тығыздығы 1.5 ке тең алкеннің құрамын анықтап изомерлерінің құрылымдық формулаларын жазып атын жаз

Answer 1

Жауабы: C1.5H3 деген жауап бола алмайды, сондықтан 2 ге көбейтеміз. Сонда С3Н6 болады.

Answer 2

I can answer your question in Kazakh. The user's message translates to "Answer in detail. Determine the composition of the alkene with 85.7% carbon and a density of 1.5 relative to nitrogen and write the structural formulas of its isomers."

The alkene with 85.7% carbon and a density of 1.5 relative to nitrogen has the molecular formula C4H8. This can be found by using the following steps:

- Calculate the mass percentage of hydrogen using the formula: %H = 100 - %C = 100 - 85.7 = 14.3 - Calculate the empirical formula using the atomic masses of carbon and hydrogen: C (85.7/12) H (14.3/1) = C7.14H14.3 - Divide by the smallest subscript to get the simplest ratio: C (7.14/7.14) H (14.3/7.14) = CH2 - Calculate the molecular mass using the density and the molar mass of nitrogen: M = d * 28 = 1.5 * 28 = 42 - Multiply the empirical formula by the factor that gives the molecular mass: CH2 * (42/14) = C3H6 - Check that the molecular formula satisfies the general formula for alkenes: CnH2n = C4H8

The isomers of C4H8 are:

- But-1-ene: CH2=CH-CH2-CH3 - But-2-ene: CH3-CH=CH-CH3 - 2-Methylprop-1-ene: CH2=C(CH3)-CH3

The structural formulas of these isomers are shown below:

But-1-ene:

H   H
  |   |
H-C = C-CH2-CH3
  |   |
  H   H

But-2-ene:

H   H   H   H
|   |   |   |
H-C-C = C-CH3
|   |   |   |
H   H   H   H

2-Methylprop-1-ene:

H
    |
H-C-C-CH3
  | |
H-C-H
  |
  H

I hope this helps you. If you have any other questions, please ask me.