Question

СРОЧНООО!!!!Пожалуйста,помогите с химией!!! Рассчитайте массу этанола и воды, необходимые для приготовления 300г 70% раствора спирта

Answer 1

ВРОДЕ КАК-ТО ТАК
300*0,7=210 грамм спирта и 300-210=90 грамм воды - без всяких уравнений.

Answer 2

Calculation of the Mass of Ethanol and Water for a 70% Alcohol Solution

To calculate the mass of ethanol and water required to prepare a 300g solution of 70% alcohol, we need to determine the mass of ethanol and water in the final solution.

Let's assume that the 70% alcohol solution is composed of 70% ethanol and 30% water. This means that for every 100g of the solution, 70g is ethanol and 30g is water.

To find the mass of ethanol in the 300g solution, we can use the following equation:

Mass of ethanol = (70/100) x 300g

Calculating this, we find:

Mass of ethanol = (0.7) x 300g = 210g.

Similarly, to find the mass of water in the 300g solution, we can use the following equation:

Mass of water = (30/100) x 300g

Calculating this, we find:

Mass of water = (0.3) x 300g = 90g.

Therefore, to prepare a 300g solution of 70% alcohol, you would need 210g of ethanol and 90g of water.

I hope this helps! Let me know if you have any further questions.