Question

1. СН3-СН=СН-СОН (альдегид) + NaHSO3 = 2. Метаналь + Cu(OH)2 = 3. СН3-СН=СН-СОH(альдегид) + Cu(OH)2 =

Answer 1

СН3-СН=СН-CHO + NaHSO3 → СН3-СН=СН-CH(OH)-SO3Na
Н-CHO + 2Cu(OH)2 → Н-COOH + Cu2O + 2H2O
СН3-СН=СН-CHO + 2Cu(OH)2 → СН3-СН=СН-COOH + Cu2O + 2H2O

Answer 2

I can chat with you in Russian. You asked me to answer in detail the following chemical reactions:

1. $CH_3-CH=CH-SO_2H$ (aldehyde) + $NaHSO_3$ = 2. Methanal + $Cu(OH)_2$ = 3. $CH_3-CH=CH-COH$ (aldehyde) + $Cu(OH)_2$ =

Here are the answers:

1. $CH_3-CH=CH-SO_2H$ (aldehyde) + $NaHSO_3$ = $CH_3-CH=CH-SO_3Na$ + $H_2O$ This is a reaction of aldehyde with sodium bisulfite, which forms a bisulfite addition compound. This reaction is used to test for the presence of aldehydes. 2. Methanal + $Cu(OH)_2$ = $Cu(CH_3O)_2$ + $H_2O$ This is a reaction of methanal with copper hydroxide, which forms copper methoxide and water. This reaction is used to synthesize copper methoxide, which is a catalyst for some organic reactions. 3. $CH_3-CH=CH-COH$ (aldehyde) + $Cu(OH)_2$ = $CH_3-CH=CH-COOH$ + $Cu_2O$ + $H_2O$ This is a reaction of aldehyde with copper hydroxide, which forms carboxylic acid, copper oxide and water. This reaction is an example of oxidation of aldehydes by copper hydroxide.

I hope this helps you with your chemistry homework.

: https://ru.wikipedia.org/wiki/%D0%90%D0%BB%D1%8C%D0%B4%D0%B5%D0%B3%D0%B8%D0%B4%D1%8B : https://www.chemguide.co.uk/organicprops/aldehydes/reduction.html : https://www.chemguide.co.uk/organicprops/aldehydes/oxidation.html Ответь+подробно.+1.+СН3-СН=СН-СОН+(альдегид)+++NaHSO3+=+2.+Метаналь+++Cu(OH)2+=++3.+СН3-СН=СН-СОH(альдегид)+++Cu(OH)2+=