Question

Ионная связь ( на примере образования молекулы NaF)

Answer 1

Ионная связь, обычно, образуется между металлом и неметаллом. Каждый элемент имеет свою степень окисления. Примером такой связи является Fe2O3(оксид железа (III)) При этом в скобках указывается валентность. Надеюсь, вопрос исчерпан.

Answer 2

Ion Formation and Ionic Bonding

Ion formation occurs when an atom gains or loses electrons to achieve a full outer shell of electrons, resulting in the formation of ions. For example, when sodium (Na) reacts with fluorine (F), sodium loses one electron to form a positively charged ion (Na+), and fluorine gains one electron to form a negatively charged ion (F-).

Formation of Sodium Fluoride (NaF)

When sodium (Na) reacts with fluorine (F), the following reaction takes place:

Na(s) + 1/2 F2(g) → NaF(s)

In this reaction, sodium (Na) loses one electron to form a sodium ion (Na+), and fluorine (F) gains one electron to form a fluoride ion (F-).

Ionic Bonding in NaF

The formation of sodium fluoride (NaF) involves ionic bonding, which is the electrostatic attraction between positively and negatively charged ions. In the case of NaF, the positively charged sodium ion (Na+) is attracted to the negatively charged fluoride ion (F-), resulting in the formation of an ionic bond between the two ions.

The resulting compound, sodium fluoride (NaF), consists of a three-dimensional array of alternating positively and negatively charged ions held together by strong electrostatic forces, forming a crystal lattice structure.

Conclusion

In summary, the formation of the molecule NaF involves the transfer of electrons between sodium and fluorine atoms, leading to the formation of sodium and fluoride ions, which are held together by strong ionic bonds to create the compound sodium fluoride.