Question

Какой объем углекислого газа (СО2) образуется при сгорании пропана (С3Н8), масса =17,6г? СРОЧНО ХЕЛП Уравнение уже составлено: С3Н8+5О2=3СО2+4Н2О

Answer 1

N(c3h8)=17,6/44=0,4моль
V(co2)=0,4*3*22,4=26,88л

Answer 2

Calculating the Volume of Carbon Dioxide Produced from the Combustion of Propane

To calculate the volume of carbon dioxide (CO2) produced from the combustion of propane (C3H8), we can use the given balanced chemical equation:

C3H8 + 5O2 → 3CO2 + 4H2O

The molar mass of propane (C3H8) is 44.1 g/mol, and the molar mass of carbon dioxide (CO2) is 44.01 g/mol.

Step 1: Convert Mass of Propane to Moles

First, we need to convert the given mass of propane to moles. The molar mass of propane is 44.1 g/mol.

Using the formula:

moles = mass / molar mass

We can calculate the moles of propane:

moles of C3H8 = 17.6 g / 44.1 g/mol

Step 2: Use Stoichiometry to Find Moles of CO2

Next, we use the stoichiometry of the balanced chemical equation to find the moles of carbon dioxide produced.

From the balanced equation, we know that 1 mole of propane (C3H8) produces 3 moles of carbon dioxide (CO2).

Step 3: Convert Moles of CO2 to Volume

Finally, we can use the ideal gas law to convert the moles of carbon dioxide to volume at standard temperature and pressure (STP), which is 0°C and 1 atmosphere pressure.

The ideal gas law is given by:

PV = nRT

Where: - P = pressure - V = volume - n = moles - R = ideal gas constant - T = temperature

At STP, the molar volume of an ideal gas is approximately 22.4 liters/mol.

Calculation:

1. Moles of C3H8 = 17.6 g / 44.1 g/mol = 0.4 moles 2. Moles of CO2 produced = 0.4 moles of C3H8 * (3 moles of CO2 / 1 mole of C3H8) = 1.2 moles 3. Volume of CO2 at STP = 1.2 moles * 22.4 liters/mol = 26.88 liters

So, the volume of carbon dioxide produced when 17.6 grams of propane (C3H8) is burned is approximately 26.88 liters at STP.